Given:
It is given that,
PQ ⊥ PS and
∠QPR = 7x-9
∠RPS = 4x+22
To find the value of ∠QPR.
Formula
As per the given problem PR lies between PQ and PS,
So,
∠QPR+∠RPS = 90°
Now,
Putting the values of ∠RPS and ∠QPR we get,
or,
or,
or,
or,
Substituting the value of in ∠QPR we get,
∠QPR =
or, ∠QPR =
Hence,
The value of ∠QPR is 40°.
Answer:
(mxt) miles
Step-by-step explanation:
hope that this is helpful.
Answer:
1, i) equation for Mike's Repair Shop = $65x + $100
ii) Amy's Auto Repair = $80x + $40
2. 65x + 100 = 80x + 40
3. x = 4
4. Therefore the number of hours at which the cost both auto repair shops are the same is x = 4 hours.
5. If it takes only three hours to fix the car the Amy' repair shop will be the cheapest because Amy's auto repair will cost = $803 + $40 = $280 and Mike's will cost = $65
3 + $100 = $295.
6. If it takes only six hours to fix the car the Amy' repair shop will be the cheapest because Amy's auto repair will cost = $806 + $40 = $520 and Mike's will cost = $65
6 + $100 = $490.
7. Amy's Auto repair service is advertising to encourage customers with quick repairs to use their service because their cost is less for quick repairs but more for lengthy repairs.
Step-by-step explanation:
i) x = number of hours worked
ii) y = total cost
1, i) equation for Mike's Repair Shop = $65x + $100
ii) Amy's Auto Repair = $80x + $40
2. 65x + 100 = 80x + 40
3. 15x = 60, therefore x = 4
4. Therefore the number of hours at which the cost both auto repair shops are the same is x = 4 hours.
5. If it takes only three hours to fix the car the Amy' repair shop will be the cheapest because Amy's auto repair will cost = $803 + $40 = $280 and Mike's will cost = $65
3 + $100 = $295.
6. If it takes only six hours to fix the car the Amy' repair shop will be the cheapest because Amy's auto repair will cost = $806 + $40 = $520 and Mike's will cost = $65
6 + $100 = $490.
7. Amy's Auto repair service is advertising to encourage customers with quick repairs to use their service because their cost is less for quick repairs but more for lengthy repairs.
