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Answer:
it's related to the factors of diffusion, in this case...
the molecule is small, the mass of it is a factor of diffusion, since it's smaller, it can diffuse quickly, since it has less weight, so it moves faster.
When the cell increases in size, the volume increases faster than the surface area, when there is more volume and less surface area, diffusion takes longer and is less effective.
Early diagnosis of childhood cancer is often difficult because the signs and symptoms are SIMILAR TO THOSE OF OTHER CHILDHOOD DISEASES.
Doctors generally find it difficult to diagnosis cancer i children because the accompany symptoms for the disease is quite similar to those of other diseases that children experience. Cancer in children usually occur very rapidly and its diagnosis in most cases typically occur at the late stage.
Answer:
Approximately 6944 glucose residues are added enzymatically per second
Explanation:
Cellulose is the main structural polysaccharides in plants. It is composed of unbranched glucose monomer units linked to each other by beta 1-4 glycosidic bonds.
The cell wall and stem of plants cells are composed of cellulose fibers. They provide rigidity and support to the plant.
In the given bamboo plant, the enzymatic addition of glucose units to the growing cellulose fiber chains results in the phenomenal growth rate of the bamboo stem.
Since each glucose unit contributes ~0.5 nm to the length of a cellulose molecule, number of glucose units required for daily growth is calculated as follows:
0.5 nm = 10⁻⁹
0.3 m/0.5 x 10⁻⁹ m = 600000000 units of glucose per day
Number of seconds in a day = 24 * 60 * 60 = 86400 seconds
Number of glucose residues added per second = 600000000/86400
Number of glucose residues added per second = 6944.4 glucose molecules per second
Therefore, approximately 6944 glucose residues are added per second
