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3 years ago

Please help, I’ll give brainliest UwU

Mathematics

1 answer:

tino4ka555 [31]3 years ago

7 0

Answer:

uwu your answer is c because jake did not like lily during the performance.

Step-by-step explanation:

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There are 820 people at a stadium.65% of them are adults,20% of them are boys,and the rest are girls. How many girls are there a

klemol [59]

100% - 65% - 20% = 15% girls.

15% = 0.15

820 * 0.15 = 123 girls

7 0

3 years ago

A scientist was measuring the daily sodium values of different foods with a soda has 35.64% of the daily value and fries have 32

uysha [10]

Answer:

68.54

Step-by-step explanation:

4 0

3 years ago

A box contains 5 red and 5 blue marbles. Two marbles are withdrawn randomly. If they are the same color, then you win $1.10; if

topjm [15]

Answer:

a) The expected value is $\frac{-1}{15}$

b) The variance is $\frac{49}{45}$

Step-by-step explanation:

We can assume that both marbles are withdrawn at the same time. We will define the probability as follows

#events of interest/total number of events.

We have 10 marbles in total. The number of different ways in which we can withdrawn 2 marbles out of 10 is $\binom{10}{2}$ .

Consider the case in which we choose two of the same color. That is, out of 5, we pick 2. The different ways of choosing 2 out of 5 is $\binom{5}{2}$ . Since we have 2 colors, we can either choose 2 of them blue or 2 of the red, so the total number of ways of choosing is just the double.

Consider the case in which we choose one of each color. Then, out of 5 we pick 1. So, the total number of ways in which we pick 1 of each color is $\binom{5}{1}\cdot \binom{5}{1}$ . So, we define the following probabilities.

Probability of winning: $\frac{2\binom{5}{2}}{\binom{10}{2}}= \frac{4}{9}$

Probability of losing $\frac{(\binom{5}{1})^2}{\binom{10}{2}}\frac{5}{9}$

Let X be the expected value of the amount you can win. Then,

E(X) = 1.10*probability of winning - 1 probability of losing = $1.10\cdot \frac{4}{9}-\frac{5}{9}=\frac{-1}{15}$

Consider the expected value of the square of the amount you can win, Then

E(X^2) = (1.10^2)*probability of winning + probability of losing = $1.10^2\cdot \frac{4}{9}+\frac{5}{9}=\frac{82}{75}$

We will use the following formula

$Var(X) = E(X^2)-E(X)^2$

Thus

Var(X) = $\frac{82}{75}-(\frac{-1}{15})^2 = \frac{49}{45}$

7 0

3 years ago

If LN=54 and LM=31, find MN

kirza4 [7]

In this item, it is unfortunate that a figure, drawing, or illustration is not given. To be able to answer this, it is assumed that these segments are collinear. Points L, M, and N are collinear, and that L lies between MN.

The length of the whole segment MN is the sum of the length of the subsegments, LN and LM. This can be mathematically expressed,
LN + LM = MN

We are given with the lengths of the smalller segments and substituting the known values,
MN = 54 + 31
MN = 85

<em>ANSWER: MN = 85</em>

7 0

3 years ago

Read 2 more answers

8 workers complete the construction of wall 6 days. How many workers are needed to complete the construction in 4 days?

ElenaW [278]

Answer:

I came up with -12

Step-by-step explanation:

8 workers = 6 days to complete

x workers = 4 days faster to complete

6/4=1.5 days faster

1.5 x 8 = 12 workers needed to complete the wall in fours days

8 0

2 years ago