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<u>Corrected Question</u>
The Venn diagram shows three types of numbers: odd (O), even (E), and prime (P). Which is represented by Ø?
(A) O ⋃ P (B)E ∩ P (C)O ⋃ E (D)E ∩ O
Answer:
(D) E ∩ O
Step-by-step explanation:
The Venn diagram is reproduced and attached below.
In the Venn diagram, the sets of Odd(O) and Even(E) numbers are disjoint, i.e. there is no intersection.
We can also say the intersection of sets O and E is the empty set.
Therefore: E ∩ O is represented by the empty set Ø.
Generally speaking, a number cannot be even and odd at the same time.
The correct option is D
Answer:
Figure 1's surface area: 550
Figure 2's surface area: 530
Figure 3's surface area: 790
So, the order of the figures' surface areas is: Figure 2 < Figure 1 < Figure 3.
Step-by-step explanation:
Bearing in mind that the surface area of a 3D object is the total area of its surface (that is the sum of the areas of its faces), we can count the number of distinct shapes in each figure, calculate their areas and add them up. Be careful not to add the faces that are "inside".
<u>Figure 1</u>
Its surface area consists of 13 squares of 5x5and 3 rectangles of 15x5
. So, its surface area is (13x25 + 3x75)
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<u>Figure 2</u>
Its surface area consists of 6 squares of 5x5, 3 rectangles of 17x5
, 1 rectangle of 13x5
and 2 triangles of base 12 feet and height 5 feet. So, its surface area is (17x5x3+6x5x5+13x5+12x5x2:2)
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<u>Figure 3</u>
Its surface area consists of 2 rectangles of 12.5x5, 1 rectangle of 11x5
, 2 triangles of base 12 feet and height 5 feet, 1 rectangle of 11x13
, 2 rectangles of 12.5x11
and 1 rectangle of 12x11
.
So, its surface area is (2x12.5x5+11x5+2x12x5:2+11x13+2x12.5x11+12x11)
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