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olasank [31]
2 years ago
7

Anybody know the answer?

Mathematics
1 answer:
stepan [7]2 years ago
8 0
Put 53/x = k/2hours I think the equation is something like that
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5/9 -7/15 divided by 1 5/9 ×7/15
Greeley [361]
Hi there,

the first part equals 4/45 and the second part equals 7/9

4/45 divided by 7/9 = 0.00141093474
Hope this helps :)<span>
</span>
3 0
3 years ago
Read 2 more answers
Find the solution of the system of equations.<br> 10x+10y=40 <br> 5x+3y=8
ddd [48]

Answer:

x = -2 & y = 6

Step-by-step explanation:

10x+10y=40

10x+10y+ -10y=40+-10y

10x=-10y+40

\frac{10x}{10} =\frac{-10y+40}{10}

x=-y+4

5x+3y=8

5(-y+4)+3y=8

-2y+20=8

-2y+20+-20=8+-20

-2y=-12

\div2

y=6

x=-y+4

x=-6+4

x=-2

Hope this helps.

7 0
2 years ago
Find each quotient. Write in simplest form. keep answer as fraction - not decimal
kirill [66]

So we are given the expression:

\frac{mn^{2}}{4} ÷ \frac{m^{2}n}{8}

When we divide fractions, we must flip the second term and change the sign to multiplication:

\frac{mn^{2}}{4} *\frac{8}{m^{2}n}

And then we multiply across:

\frac{mn^{2}}{4} *\frac{8}{m^{2}n}= \frac{8mn^{2}}{4m^{2}n}

Then we can break apart all of the like variables for simplification:

\frac{8mn^{2}}{4m^{2}n}=\frac{8}{4} * \frac{m}{m^{2}} *\frac{n^{2}}{n}

When we simplify variables through division, we subtract the exponent of the numerator from the exponent of the denominator. So we then have:

\frac{8}{4} =2

\frac{m}{m^{2}}=m^{-1} =\frac{1}{m}

\frac{n^{2}}{n}=n^{1}=\frac{n}{1}

So then we multiply all of these simplified parts together:

\frac{2}{1}*\frac{1}{m}*\frac{n}{1}   =\frac{2n}{m}

So now we know that the simplified form of the initial expression is: \frac{2n}{m}.

3 0
3 years ago
Tell whether the given value is a solution of the inequality
topjm [15]

Answer:

the given value <u>is</u> a solution of the inequality

Step-by-step explanation:

12 + m ≥ -4 if m = -3

12 + (-3) ≥ -4

9 ≥ -4

9 is greater than or equal to -4

5 0
2 years ago
Given that 'n' is any natural numbers greater than or equal 2. Prove the following Inequality with Mathematical Induction
Oliga [24]

The base case is the claim that

\dfrac11 + \dfrac12 > \dfrac{2\cdot2}{2+1}

which reduces to

\dfrac32 > \dfrac43 \implies \dfrac46 > \dfrac86

which is true.

Assume that the inequality holds for <em>n</em> = <em>k </em>; that

\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k > \dfrac{2k}{k+1}

We want to show if this is true, then the equality also holds for <em>n</em> = <em>k</em> + 1 ; that

\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k + \dfrac1{k+1} > \dfrac{2(k+1)}{k+2}

By the induction hypothesis,

\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k + \dfrac1{k+1} > \dfrac{2k}{k+1} + \dfrac1{k+1} = \dfrac{2k+1}{k+1}

Now compare this to the upper bound we seek:

\dfrac{2k+1}{k+1}  > \dfrac{2k+2}{k+2}

because

(2k+1)(k+2) > (2k+2)(k+1)

in turn because

2k^2 + 5k + 2 > 2k^2 + 4k + 2 \iff k > 0

6 0
2 years ago
Read 2 more answers
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