In order to factorate the trinomial, let's first find its roots using the quadratic formula:
![\begin{gathered} b^2-4ac=12^2-4\cdot4\cdot9=144-144=0 \\ x_1=x_2=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}=\frac{-12+0}{2\cdot4}=-\frac{12}{8}=-\frac{3}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20b%5E2-4ac%3D12%5E2-4%5Ccdot4%5Ccdot9%3D144-144%3D0%20%5C%5C%20x_1%3Dx_2%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D%3D%5Cfrac%7B-12%2B0%7D%7B2%5Ccdot4%7D%3D-%5Cfrac%7B12%7D%7B8%7D%3D-%5Cfrac%7B3%7D%7B2%7D%20%5Cend%7Bgathered%7D)
Now we can write the trinomial in the form:
So we have that:
So 2x + 3 is a factor of the trinomial, therefore the answer is D.
Answer: 6.50x + 3.50 < 23
Step-by-step explanation:
I believe this is correct because the total of the one-time fee and the money per game she played, should be less than $23
<h3>
Answer: C) 2</h3>
The term 2 is really the same as 2*1 = 2x^0. Recall that anything (except 0) to the zeroth power is 1. So the rule is x^0 = 1 when x is nonzero.
Looking at 2x^0, we see that 2 is the coefficient here because it is the constant being multiplied with the variable term.
Answer:
1. quadrilateral; not regular
2. quadrilateral; regular
3. octagon; not regular
4. hexagon; regular
5. triangle; regular
6. pentagon; not regular
Answer:
i think it might be 118.4
Step-by-step explanation:
