Answer:
Lg fortune network unlocking is a method through which lg fortune can be used with any network or provider
Explanation:
When Any Network (e.g At&t, Cricket etc.) launched any smart phone (e.g lg fortune) they barricade their devices with a unique code, This blockade can be removed through sim network unlock pin. The only way to get it, is the phone`s imei which is also unique of each and every phone/tablet.
When you order it by sending the imei to a legitimate source like 24x7unlockcodes.com, They process it & derived a 100% working Lg Fortune unlock code. It safely unlock your Cricket Devices in skillful manners without damaging it. You can also get it from any cell phone shop.
Precision, specificity is related to the accuracy of the information with respect to the subject at hand. Precision is the only answer that makes sense.
Answer:
B
Explanation:
When you initialize an instance of FunEvent(tags, year) and assign it to bc. The instance variables in this case are: self.tags = ["g", "ml"] and self.year = 2022. But then you alter tags, which will also change self.tags, since self.tags is a reference to the list you passed in as an argument. This is not the case when you do year=2023 because, first of all, integers are not mutable, and also because even if somehow integers were mutable, you're not changing the object in-place, you're simply changing the where the "variable" is pointing to. So for example if you did tags = ["g", "ml", "bc"] instead of tags.append("bc"), it would also not change the value of the instance variable "tags", because you wouldn't be changing the object in-place. So when you print(bc), the instance variables will be ["g", "ml", "bc"] and 2022. When you try to print an object, it call try to convert it into a string using the __str__ magic method. In this case it will return a string formatted as "Event(tags={self.tags}, year={self.year}) which will output "Event(tags=['g', 'ml', 'bc'], year=2022)" So the correct answer is B
<span>the machines, wiring, and other physical components of a computer or other electronic system.</span>
Answer:
Multiple-user licence.
Explanation:
A multiple-user licence allows the software to be accessed by the maximum number of users specified within the licence. In this scenario, it is 5 students, the connections are concurrent, meaning at any given time there can only be five users running the software. The software can be installed on more than 5 computers, but the number of active users is limited to 5.
