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Minchanka [31]
2 years ago
15

HELPPPP i’ll give brainliest if it’s right!!!

Mathematics
2 answers:
STALIN [3.7K]2 years ago
5 0

Answer:

the answer is A and D

Step-by-step explanation:

ioda2 years ago
4 0

Answer:

\sqrt{19} & \sqrt{48}

Step-by-step explanation:

\sqrt{81} = 9

\sqrt{64} = 8

Both are rational, so they are not correct

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Which of the functions below could have created this graph?
Brums [2.3K]

Answer:

need pic

Step-by-step explanation:

3 0
3 years ago
can someone please tell me how to do 2x=3y and 4x-3y=12 using substitution to solve the system of equations.
maw [93]

Answer:

Step-by-step explanation:

you divide the two to the y, which is x=3/2y

then, you simplify the second equation to y, which is -3y= -4x+12

then, you substitute the x=3/2y into the second equation,

-3y = -6+12

-3y = 6

y = -2

Substitute the y into the first equation, x= 3/2y,

x = -3

5 0
3 years ago
Determine the domain and range of the graph.
nirvana33 [79]

Answer:

Domain [-4,4]

Range [-2,2]

Step-by-step explanation:

The domain is the x-values of the graph and the range in the y-values. When writing domain and range it should be from least to greatest. So to find the domain find the lowest x-value on the graph and then the highest. Next, do the same for y-values. Finally, either surround each value with parentheses or bracket, the difference is that brackets mean that value is included, while parentheses mean that value is not actually on the graph.

In this case, the lowest x-value is -4 and the highest is 4, both values are included as signified by the closed circles, therefore the domain is [-4,4]. The lowest y value is -2 and the highest is 2, both are included, therefore the range is [-2,2].

4 0
2 years ago
Express 0.032 as a fraction in lowest terms
SIZIF [17.4K]

Answer:

4/125

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
3.x2 + 4x + 5 for x = -2<br>please help asap​
Law Incorporation [45]
Your equation is a little messed up comment me the equation you need help with
8 0
3 years ago
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