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chubhunter [2.5K]
3 years ago
11

a cone has a radius of 1.2 inches and a height of 2.9 inches. What is the volume, rounded to the nearest tenth of a cubic inch,

of the cone? possible answers are A.)3.6 B.) 4.4 C.) 10.6 D.) 13.1
Mathematics
1 answer:
n200080 [17]3 years ago
3 0
The volume of the cone is defined as 
Volume = pi * r^2 * (h/3)
Volume = pi * 1.2^2 * (2.9/3)
Volume = 4.37310 in^3

If the answer is <span>rounded to the nearest tenth of a cubic inch,
then the final answer is letter (B) 4.4 in^3</span>
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What is the length of the hypotenuse? Answer : 17
leonid [27]

Answer:

Below.

Step-by-step explanation:

Finding the hypotenuse:

Recall the formula of Pythagoras'theorem,

  • (Hypotenuse)² = (Base)² + (Perpendicular)²

Given that base = 8 and perpendicular = 15

Plugging the values,we obtain

  • H² = 8² + (15)²
  • H² = 64 + 225
  • H² = 289
  • H = √(17*17)
  • H = 17

Now applying trigonometric functions:

Recall SOHCAHTOA , it's very helpful.

Sin θ = Sin A = Opposite/Hypotenuse

  • Sin A = 15/17 ≈ 0.88

cos θ = cos A = Adjacent/Hypotenuse

  • cos A = 8/17 ≈ 0.47

Tan θ = tan A = Opposite/Adjacent

  • tan A = 15/8 ≈ 1.88

Note: The values in decimal are rounded to nearest hundredth.

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2 years ago
Which is the graph of the linear inequality y &lt; 3x + 1?
mestny [16]
Start at +1 on the x axis and then use 3/1 for rise over run. So you will start at +1 and then from that point rise 3 run 1
5 0
3 years ago
Factor by grouping <br> 6x^2-12x+x-2<br> factor completely
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Uh ye here you go stranger hoped this help

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Match the parabolas represented by the equations with their foci.
Elenna [48]

Function 1 f(x)=- x^{2} +4x+8


First step: Finding when f(x) is minimum/maximum
The function has a negative value x^{2} hence the f(x) has a maximum value which happens when x=- \frac{b}{2a}=- \frac{4}{(2)(1)}=2. The foci of this parabola lies on x=2.

Second step: Find the value of y-coordinate by substituting x=2 into f(x) which give y=- (2)^{2} +4(2)+8=12

Third step: Find the distance of the foci from the y-coordinate
y=- x^{2} +4x+8 - Multiply all term by -1 to get a positive x^{2}
-y= x^{2} -4x-8 - then manipulate the constant of y to get a multiply of 4
4(- \frac{1}{4})y= x^{2} -4x-8
So the distance of focus is 0.25 to the south of y-coordinates of the maximum, which is 12- \frac{1}{4}=11.75

Hence the coordinate of the foci is (2, 11.75)

Function 2: f(x)= 2x^{2}+16x+18

The function has a positive x^{2} so it has a minimum

First step - x=- \frac{b}{2a}=- \frac{16}{(2)(2)}=-4
Second step - y=2(-4)^{2}+16(-4)+18=-14
Third step - Manipulating f(x) to leave x^{2} with constant of 1
y=2 x^{2} +16x+18 - Divide all terms by 2
\frac{1}{2}y= x^{2} +8x+9 - Manipulate the constant of y to get a multiply of 4
4( \frac{1}{8}y= x^{2} +8x+9

So the distance of focus from y-coordinate is \frac{1}{8} to the north of y=-14
Hence the coordinate of foci is (-4, -14+0.125) = (-4, -13.875)

Function 3: f(x)=-2 x^{2} +5x+14

First step: the function's maximum value happens when x=- \frac{b}{2a}=- \frac{5}{(-2)(2)}= \frac{5}{4}=1.25
Second step: y=-2(1.25)^{2}+5(1.25)+14=17.125
Third step: Manipulating f(x)
y=-2 x^{2} +5x+14 - Divide all terms by -2
-2y= x^{2} -2.5x-7 - Manipulate coefficient of y to get a multiply of 4
4(- \frac{1}{8})y= x^{2} -2.5x-7
So the distance of the foci from the y-coordinate is -\frac{1}{8} south to y-coordinate

Hence the coordinate of foci is (1.25, 17)

Function 4: following the steps above, the maximum value is when x=8.5 and y=79.25. The distance from y-coordinate is 0.25 to the south of y-coordinate, hence the coordinate of foci is (8.5, 79.25-0.25)=(8.5,79)

Function 5: the minimum value of the function is when x=-2.75 and y=-10.125. Manipulating coefficient of y, the distance of foci from y-coordinate is \frac{1}{8} to the north. Hence the coordinate of the foci is (-2.75, -10.125+0.125)=(-2.75, -10)

Function 6: The maximum value happens when x=1.5 and y=9.5. The distance of the foci from the y-coordinate is \frac{1}{8} to the south. Hence the coordinate of foci is (1.5, 9.5-0.125)=(1.5, 9.375)

8 0
3 years ago
Express 20 gallons in liters
lys-0071 [83]

Answer: 75.7082

Step-by-step explanation:

7 0
2 years ago
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