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3 years ago

What is the domain of the function y=^3 sqrt x-1

2 answers:

4 0

Yes i is going on the same time as he has a few things that i need to help your brother bye bye uh hi what bye bye girl bye on my fyp yeah yeah

Anettt [7]3 years ago

3 0

Answer:

The domain is all real numbers

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As a part of your project studying tipping behavior, you ask people the question, How much should you tip a grocery bagger for c

Darina [25.2K]

Don’t have idea for this work can of confused

6 0

2 years ago

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Yea I can do tomorrow it would take me to get the money back to you

Tems11 [23]

Given, the equation that represents the height of an object:

$y(t)=100t-16t^2$

First, we will find the velocity of the object which is the first derivative of the height using the method of the limits

$\frac{dy}{dt}=\lim_{h\to a}\frac{y(3+h)-y(3)}{(3+h)-(3)}$

We will find the value of the function y(t) when t = 3, and when t = 3+h

$\begin{gathered} y(3+h)=100(3+h)-16(3+h)^2 \\ y(3+h)=300+300h-16(9+6h+h^2) \\ y(3+h)=300+300h-144-96h-16h^2 \\ y(3+h)=156+4h-16h^2 \\ y(3)=100(3)-16(3)^2=156 \end{gathered}$

Substitute y(3+h) and y(3) into the expression of the limit

$\begin{gathered} \frac{dy}{dt}|_{t=3}=\lim_{h\to a}\frac{156+4h-16h^2-156}{3+h-3}=\lim_{h\to a}\frac{4h-16h^2}{h} \\ \\ \frac{dy}{dt}|_{t=3}=\lim_{h\to a}(4-16h) \end{gathered}$

Where a = 0

d) compute the instantaneous velocity at t = 3

$\frac{dy}{dt}|_{t=3}=100-16*2*3=4$

So, the answer will be:

$\begin{gathered} \frac{dy}{dt}|_{t=3}=\lim_{h\to a}(4-16h) \\ a=0 \\ \\ \frac{dy}{dt}|_{t=3}=4\text{ ft/sec} \end{gathered}$

5 0

1 year ago

The unit rate of frames animated per minute is 1.5 and I animated 4 frames in 6 minutes, how would I write this on a table like

irina [24]

Answer:

i dont know

Step-by-step explanation:

3 0

3 years ago

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to make a sandwich steve uses 1/8 Ib of ham and 1/5 Ib of cheese. How much more cheese than ham does he use

mote1985 [20]

1/5-1/8= 3/40 Hope it helps <3

6 0

2 years ago

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A sphere with surface area of 154cm² is fit exactly in cubical box, Use π 22/7

Serga [27]

Answer:

<h2><u>Answer</u><u> </u><u>:</u><u>-</u></h2>

Surface area of sphere = 4 π r²

154 = 4 × 22/7 × r²

154 = 88/7 × r²

154 × 7/88 = r²

12.25 = r²

3.5 = r

Now

Volume of sphere = 4/3 × π r³

Volume = 4/3 × 22/7 × (3.5)³

Volume = 88/21 × 42.875

Volume = 154 cm³

Volume of sphere = Volume of cube

Volume of cube = 154 cm³

6 0

2 years ago