Answer:
Step-by-step explanation:
we have

we know that
The sum of a quadratic equation and a linear equation will be a quadratic equation
so
Combine like terms

Answer:
Step-by-step explanation:
you have two supplementary angles,
both added up=180
7y+5y=12y
12y=180y=15
angle DBC=7y=15*7=105
The equation of any given circle is:

where (h, k) is the center and r is the radius.
In the problem, we are given the center, and the radius. When we plug them in:

we got the formula of the circle.
Answer: x = 37.8
Step-by-step explanation: We start with triangle ABC with two sides given as 15 and 18. We shall make angle C the reference angle and thereby calculate the third side, line BC.
Since we have the opposite side as 15, and the adjacent side (which lies between the reference angle and the right angle) as 18, we can use the tangent of the angle C
Tan C = Opp/Adj
Tan C = 15/18
Tan C = 0.8333
From our table of values/use of the calculator
Tan C = 39.8
Angle C in triangle ACB = Angle C in triangle ECD (Opposite angles are equal).
That takes us to triangle ECD, since the reference angle is known (39.8) and the opposite side is also given (31.5), we can now calculate the adjacent which is side x.
Tan C = Opp/Adj
Tan 39.8 = 31.5/x
when you cross multiply, x moves to the left hand side, while Tan 39.8 moves to the right hand side
x = 31.5/Tan 39.8
x = 31.5/0.8333
<u>x = 37.8</u>