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2 years ago

Show that the function of f(x) = a - x is its own inverse for all real numbers a

Mathematics

1 answer:

tatuchka [14]2 years ago

5 0

f(x) = a - x

y = a - x

y + x = a - x + x

y + x = a

y + x - y = a - y

x = a - y

f-¹(x) = a - x

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98 x 63 – 32 x 69 =

Dahasolnce [82]

Answer:

3966

Step-by-step explanation:

Use order of operations to solve this problem:

Parentheses
Exponents
Multiply (Left to right)
Divide (Left to right)
Addition
Subraction

In your case, there are no parentheses or exponents, so we can skip right the the multiply and divide step. The first multiplication is 98*63=6174. The next step is to do 32*69=2208. Then you minus 6174-2208=3966.

Hope this helps!

7 0

2 years ago

What is the square root of -1?

NeX [460]

Answer:

Step-by-step explanation:

3 0

3 years ago

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The equation of the line that contains diagonal HM is y = 2/3 x + 7.

nirvana33 [79]

Answer:

The slope of the line that contains diagonal OE will be = -3/2

Step-by-step explanation:

We know the slope-intercept form of the line equation

y = mx+b

Where m is the slope and b is the y-intercept

Given the equation of the line that contains diagonal HM is y = 2/3 x + 7

y = 2/3 x + 7

comparing the equation with the slope-intercept form of the line equation

y = mx+b

Thus, slope = m = 2/3

We know that the diagonals are perpendicular bisectors of each other.

As we have to determine the slope of the line that contains diagonal OE.

As the slope of the line that contains diagonal HM = 2/3

We also know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line.

Therefore, the slope of the line that contains diagonal

OE will be = -1/m = -1/(2/3) = -3/2

Hence, the slope of the line that contains diagonal OE will be = -3/2

3 0

2 years ago

Is 7/8 or 11/10 closer to 1? How did you decide anybody help please?

erik [133]

Let

A-----> $\frac{7}{8}$

B-----> $\frac{11}{10}$

C-----> $1$

we know that

Point A-------> Multiply numerator and denominator by $10$

$\frac{7*10}{8*10} =\frac{70}{80}$

Point B-------> Multiply numerator and denominator by $8$

$\frac{11*8}{10*8} =\frac{88}{80}$

Point C-------> Multiply numerator and denominator by $80$

$\frac{1*80}{1*80} =\frac{80}{80}$

Find the distance Point A to Point C

$\frac{80}{80} -\frac{70}{80} =\frac{10}{80}$

Find the distance Point B to Point C

$\frac{88}{80} -\frac{80}{80} =\frac{8}{80}$

therefore

$\frac{8}{80} < \frac{10}{80}$

Point B is closer to Point C

$\frac{11}{10}$ is closer to $1$

the answer is

$\frac{11}{10}$ is closer to $1$

5 0

2 years ago

Read 2 more answers

Please help me with vivid explanation

Ivanshal [37]

Answer:

864 m²

Step-by-step explanation:

First calculate the total area of the rectangular field

The area of a rectangle is given by the product of the length and the width

let A be the total area

A = 100*120

A = 12000 m²

Calculate the area of the small rectangles

Let A' be the total area of the four small rectangles and A" the area of one small rectangle

A' = 4 A"
A' = 4 [( $\frac{120-4}{2}$ )*( $\frac{100-4}{2}$ )]
A' = 4*58*48
A' = 11136 m²

Substract the A' from A to get the area of the road

Let A"' be the area of the road

A"' =A-A'

A"' = 12000-11136

A"' = 864 m²

3 0

2 years ago