2 years ago

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1 answer:

maks197457 [2]2 years ago

4 0

$4x^2+32x-28=0\ \ \ |:4\\\\x^2+8x-7=0\ \ \ |+7\\\\x^2+8x=7\\\\x^2+2x\cdot4=7\ \ \ |+4^2\\\\x^2+2x\cdot4+4^2=7+4^2\\\\(x+4)^2=7+16\\\\(x+4)^2=23\\\\Answer:\ B.(x+4)^2=23$

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