Kelly collected $15, $15, $25, and $29 in the last 4 donations for the class fundraiser. The mean of the donations is _____?
2 answers:
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Answer:
The minimum head breadth that will fit the clientele is 4.4 inches.
The maximum head breadth that will fit the clientele is 7.8 inches.
Step-by-step explanation:
Let <em>X</em> = head breadths of men that is considered for the helmets.
The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 6.1 and standard deviation, <em>σ</em> = 1.
To compute the probability of a normal distribution we first need to convert the raw scores to <em>z</em>-scores using the formula:
It is provided that the helmets will be designed to fit all men except those with head breadths that are in the smallest 4.3% or largest 4.3%.
Compute the minimum head breadth that will fit the clientele as follows:
P (X < x) = 0.043
⇒ P (Z < z) = 0.043
The value of <em>z</em> for this probability is:
<em>z</em> = -1.717
*Use a <em>z</em>-table.
Compute the value of <em>x</em> as follows:
Thus, the minimum head breadth that will fit the clientele is 4.4 inches.
Compute the maximum head breadth that will fit the clientele as follows:
P (X > x) = 0.043
⇒ P (Z > z) = 0.043
⇒ P (Z < z) = 1 - 0.043
⇒ P (Z < z) = 0.957
The value of <em>z</em> for this probability is:
<em>z</em> = 1.717
*Use a <em>z</em>-table.
Compute the value of <em>x</em> as follows:
Thus, the maximum head breadth that will fit the clientele is 7.8 inches.
Consider the contrapositive of the statement you want to prove.
The contrapositive of the logical statement
<em>p</em> ⇒ <em>q</em>
is
¬<em>q</em> ⇒ ¬<em>p</em>
In this case, the contrapositive claims that
"If there are no scalars <em>α</em> and <em>β</em> such that <em>c</em> = <em>α</em><em>a</em> + <em>β</em><em>b</em>, then <em>a₁b₂</em> - <em>a₂b₁</em> = 0."
The first equation is captured by a system of linear equations,
or in matrix form,
If this system has no solution, then the coefficient matrix on the right side must be singular and its determinant would be
and this is what we wanted to prove. QED