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3 years ago

I have a set of numbers 125, 200, 150, 75, 275, & 300 what is the most reasonable interval answer choices 5,10,25 & 100

Mathematics

1 answer:

il63 [147K]3 years ago

5 0

I would say 25 because every number is divisible to an integer by 25 not all are divisible by 100 5 and 10

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The midpoint of AB is M(-4,2). If the coordinates of A are (-6,5), what are the

-Dominant- [34]

Answer:

(-2,-1)

Step-by-step explanation:

Midpoints are found when you do ([x(subscript A) + x(subscript B)]/2, [y(subscript A) + y(subscript B)]. Therefore your equation (for x of B) should look like this:

-4 = ([-6+x]/2)

After you solve for x, you should have gotten -2 for x.

Then you do the same for y:

2 = ([5+y]/2)

You should get -1. Your final answer should be (-2, -1)

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2 years ago

PLATO USERS NEEDED - 50 POINTS

rusak2 [61]

The answer is 2 because you multiply 9.8 times the mass and that will give you your answer

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3 years ago

Read 2 more answers

2. make sure you show all your work for full points. what is z?

LenKa [72]

Answer:

I don't understand what the means

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1 year ago

The Wall Street Journal reported that automobile crashes cost the United States $162 billion annually (2008 data). The average c

ivanzaharov [21]

Answer:

$n=(\frac{2.326(500)}{120})^2 =93.928 \approx 94$

So the answer for this case would be n=94 rounded up to the nearest integer

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma= 500$ represent the population standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =120 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The confidence2 level is 98% or 0.98 then the significance level would be $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , the critical value for this case would be $z_{\alpha/2}=2.326$ , replacing into formula (b) we got: