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allsm [11]
2 years ago
10

Guys help.. this is overdue..

Mathematics
2 answers:
charle [14.2K]2 years ago
6 0
5x55=275 then you subtract 95 from 275 and that will give you 180 that’s ur answer
loris [4]2 years ago
4 0
So if his homework takes 25 minutes , and his math takes m minutes , and then as a while it takes h minutes, here’s an example of two equations you can use ;
M+25= h of 25+m=h you can do either one as you please because it doesn’t matter the order as long as they
Both equal h !! Hope this helps , sorry that it’s overdue :( have a great day:))))
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Show that 5(3y-2)=15y-10 for at least 5 values of y
Vsevolod [243]
<span>Solving the equation for Y = 1. 5 * (3 * 1 - 2) = 15 * 1 - 10 5 * (3 - 2) = 15 -10 5 * 1 = 5 5 = 5 Solving the equation for Y = 2. 5 * (3 * 2 - 2) = 15 * 2 - 10 5 * (6 - 2) = 30 -10 5 * 4 = 20 20 = 20 Solving the equation for Y = 4. 5 * (3 * 4 - 2) = 15 * 4 - 10 5 * (12 - 2) = 60 -10 5 * 10 = 50 50 = 50 Solving the equation for Y = 8. 5 * (3 * 8 - 2) = 15 * 8 - 10 5 * (24 - 2) = 120 -10 5 * 22 = 110 110 = 110 Solving the equation for Y = 9. 5 * (3 * 9 - 2) = 15 * 9 - 10 5 * (27 - 2) = 135 -10 5 * 25 = 125 125 = 125 This proves that the equation holds good for at least 5 values of 'y', which are 1, 2, 4, 8 and 9. However, it can be proved that the equation holds good for any value of y. Expression 5(3y-2) can be simplified to 15y -10 which is the same expression on the right had side of the equation provided. So, equation 5(3y-2)=15y-10 is actually 15y-10=15y-10 and since this is true for all values of y, it has been proved that it is true for at least 5 values of y.</span>
7 0
3 years ago
write a slope intercept equation for a line passing through the point (2,-2) that is parallel and perpendicular to the line x=-1
vekshin1

You would need two different lines to complete this as lines cannot be both parallel and perpendicular (these are opposites). The answers would be:

Parallel: x = 2

Perpendicular: y = -2

In order to find these, we first need to see that the original line of x = -1 is a horizontal line. Therefore, any line that is parallel should be horizontal as well. To get a horizontal line through the point (2, -2), the only option is x = 2.

Similarly, with the perpendicular line, if the original line is horizontal, the new line must be vertical. The only vertical line that goes through (2, -2) is y = -2.

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2 years ago
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Your account is gonna be negative 48$
4 0
3 years ago
Read 2 more answers
HELP ASAP!!!!!!!
Musya8 [376]

I believe the correct option is C.

8 0
3 years ago
Hey!! I need this answer fast, no cap allowed!!
KIM [24]

1

(5(0)+1/2)2

(1/2)2

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1

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2 years ago
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