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3 years ago

16, -6.4, 2.56, ..., 6th term The 6th term of the sequence is

Mathematics

1 answer:

AlekseyPX3 years ago

4 0

Answer:

the 6th term is = -0.16384

Step-by-step explanation:

Notice this is a geometric sequence with first term 16, and common ratio (-0.4)

Therefore the first 6 terms of the sequence are:

a1 = 16

a2 = 16 * (-0.4) = -6.4

a3 = -6.4 * (-0.4) = 2.56

a4 = 2.56 * (-0.4) = -1.024

a5 = -1.024 * (-0,4) = 0.4096

a6 = 0.4096 * (-0.4) = -0.16384

The the 6th term is = -0.16384

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$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
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\\ \quad \\
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\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template above in mind, let's see this one

$\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

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check the picture below

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