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rodikova [14]
3 years ago
13

A machine costs 7500. Its value decreases by 5% every year due to usage. what will be its price after 1 year?​

Mathematics
1 answer:
Arada [10]3 years ago
5 0

Answer:

12000 will be the price of machine after 1year.

Step-by-step explanation:

As i got.

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<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{
Jlenok [28]

Answer:

x>2

Step-by-step explanation:

When given the following inequality;

(x^2+x-3):(x^2-4)\geq1

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

\frac{x^2+x-3}{x^2-4}\geq1

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

\frac{x^2+x-3}{x^2-4}-1\geq0

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0

Perform the operation on the other side distribute the negative sign and combine like terms;

\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0

Factor the equation so that one can find the intervales where the inequality is true;

\frac{x+1}{(x-2)(x+2)}\geq0

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

-1, 2, -2

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

x\leq-2\\-2

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

x\leq-2   -> negative

-2   -> neagtive

-1\leq x   -> neagtive

x>2   -> positive

Therefore, the solution to the inequality is the following;

x>2

6 0
3 years ago
abduls average speed is 40 mph in heavy traffic and his average speed is 50 mph in light traffic for 1 hour and light traffic fo
alexira [117]

Answer:

over 9000

^^^

Liar.

Step-by-step explanation:

over 9000

^^^

Liar.

3 0
3 years ago
the cost of running an appliance varies jointly as the number of watts used, the hours of operation, and the cost per kilo-watt
zhuklara [117]
Suppose:
C=cost
c=cost per kilo-watt hour
w=number of watts
h=number of hours
thus
C=kwhc
where:
k=constant of proportionality:
k=C/(whc)
but
C=15 when w=6000, h=10/60=1/6 hours, c=7.5 cents per kw/h
thus
k=15/(6000*1/6*7.5)
k=0.002
thus:
C=0.002(whc)
hence:
when 
h=70*2=140=140/6=70/3 hours the cost will be:
C=0.002(6000*70/3*7.5)
C=2100 cents
C=$21

7 0
3 years ago
(5x²+2) - (-4x²+7)+(-3x²-5)
svp [43]

Answer:

6x^2   -10

Step-by-step explanation:

(5x²+2) - (-4x²+7)+(-3x²-5)

Distribute the minus sign

(5x²+2) +4x²-7 +(-3x²-5)

Combine like terms

5x²+4x²-3x²  +2-7-5

6x^2              -10

6 0
3 years ago
Write an equation of the line that passes through (−5, −2)(−5, −2) and is parallel to y=23x+1y=23x+1.
Klio2033 [76]
Assuming you meant 2/3
y=2/3x+1 and (-5,-2)

paralell means same slope
y=mx+b
m=slope

y=2/3x+1
sllope=2/3

point slope
y-y1=m(x-x1)
for slope=m
a point is (x1,y1)

slope=2/3
point=(-5,-2)

y-(-2)=2/3(x-(-5))
y+2=2/3(x+5)
or
y=2/3x+16/3

7 0
3 years ago
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