Answer:
4
Step-by-step explanation:
I think I'm not that sure
Differentiate g using the power rule:




The critical points of g occur where g' is zero or undefined.
We have

and the derivative is undefined for

Answer:
60 degrees
Step-by-step explanation:
It is less than 90 degrees
Length = √(y2-y1)² + (x2-x1)²
l = √(5 - 5)² + (9 + 2)²
l = √0² + 11²
l = √121
l = 11
In short, Your Answer would be 11 units
Hope this helps!