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GuDViN [60]
3 years ago
14

Given q(x)=3x and r(x)=x2. What is (r∘q)(2)? 36 10 12 24

Mathematics
1 answer:
zmey [24]3 years ago
3 0

Answer:

the answer would be 36.

Step-by-step explanation:

and here go you would get it

R(-5) = -3*(-5) - 4

R(-5) = 15 - 4

R(-5) = 11

Q(X)=3X+3

Q(11) = 3*11 + 3

Q(11) = 33 + 3

Q(11) = 36

So, (Q(R(-2) = 36

hope it is correct..

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58,319 is the answer lol
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Help me with this please anyone x
Murrr4er [49]
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6 0
4 years ago
The local pre-school ordered all new bicycles and tricycles for the new school year. Each bicycle and tricycle is shipped in its
mrs_skeptik [129]
There are 16 boxes total, and 45 wheels total. 

we know that each bicycle/tricycle is in it's own box. 
i'm going to use the variable "b" for bicycle and "t" for tricycle

b + t = 16 
(because b is the amount of bicycles and t is the amount of tricycles) 

now we know that there are 45 wheels total. 
there are 2 wheels for a bicycle and 3 wheels for a tricycle

2b + 3t = 45 

now we have a system of equations
b + t = 16
2b + 3t = 45 

You can solve this multiple ways, but I'm going to use substitution. 
b + t = 16 can also be written as b = 16 - t (if you subtract both sides by t) 
then we can substitute this b = 16 - t into the other equations

2(16 - t) + 3t = 45

32 - 2t + 3t = 45
32 + t = 45
t = 13 

now you can plug that back into the original equations

b + 13 = 16 
b = 3

2b + 3(13) = 45
2b + 39 = 45
2b = 6
b = 3

If you have any more questions, feel free to ask!

5 0
3 years ago
What’s 6 5/15 plus 8 1/5
rodikova [14]

Answer:

14 8/15

Step-by-step explanation:

6  5/15 + 8 1/5 = 14 8/15

(you see how many times [8 1/5] can go to get to __3/15)

8 0
4 years ago
Read 2 more answers
Given f(x)=2x^2+3x-5 for what values of x is f(x) positive
kow [346]

Answer:

The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)

Step-by-step explanation:

we have

f(x)=2x^{2}+3x-5

This is a vertical parabola open upward (the leading coefficient is positive)

The vertex is a minimum

The coordinates of the vertex is the point (h,k)

step 1

Find the vertex of the quadratic function

Factor the leading coefficient 2

f(x)=2(x^{2}+\frac{3}{2}x)-5

Complete the square

f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-5-\frac{9}{8}

f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-\frac{49}{8}

Rewrite as perfect squares

f(x)=2(x+\frac{3}{4})^{2}-\frac{49}{8}

The vertex is the point (-\frac{3}{4},-\frac{49}{8})

step 2

Find the x-intercepts (values of x when the value of f(x) is equal to zero)

For f(x)=0

2(x+\frac{3}{4})^{2}-\frac{49}{8}=0

2(x+\frac{3}{4})^{2}=\frac{49}{8}

(x+\frac{3}{4})^{2}=\frac{49}{16}

take the square root both sides

x+\frac{3}{4}=\pm\frac{7}{4}

x=-\frac{3}{4}\pm\frac{7}{4}

x_1=-\frac{3}{4}+\frac{7}{4}=1

x_2=-\frac{3}{4}-\frac{7}{4}=-2.5

therefore

The function f(x) is negative in the interval (-2.5,1)

The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)

see the attached figure to better understand the problem

6 0
4 years ago
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