Question

What is the perimeter of this triangle?

Answer 1

Answer: $a+b+\sqrt{a^{2}+b^{2}}$

Step-by-step explanation:

The distance from (0,b) to (0,0) is b.

The distance from (0,a) to (0,0) is a.

Using the Pythagorean theorem, the distance from (0,b) to (a,0) is $\sqrt{a^{2}+b^{2}}$

So, the perimeter is $\boxed{a+b+\sqrt{a^{2}+b^{2}}}$