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masya89 [10]
3 years ago
11

Need help please ^-^

Mathematics
1 answer:
Triss [41]3 years ago
6 0

Factored form: (x + 1/5)(x + 1/4)

Foil: x^2 + 1/4x + 1/5x + 1/20

Simplify: x^2 + 9/20x + 1/20

Hope this helps!

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A television costs $270.25 including 15% tax. How much of cost is the tax
My name is Ann [436]

Answer:

229.7125

Step-by-step explanation:

4 0
3 years ago
When rolling a number cube 600 Times, predict the relative frequency of rolling a 3 or 6
Flauer [41]

Answer:

The frequency of rolling a 3 or a 6 would be the same even if you try thousands or millions times.

The probability of rolling a 3 is: 1/ total outcomes probability = 1/6

The probability of rolling a 6 is: 1/ total outcomes probability = 1/6

The probability of rolling a 6 or a 3 = 2/ total outcomes probability = 2/6 = 1/3

Therefore, if you rolling the cube 600 times, the probability of rolling a 3 or a 6 is still 1/6. If 3 and 6 are both allowed, the probability would become 1/3

Hope this helped :3

7 0
3 years ago
Exit Ticket/CFU/You try:<br> Find the difference: (3 - 2i) - (5 - 6i). Show your work below.
jok3333 [9.3K]
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4 0
3 years ago
A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m
photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

  • Mass of the car, v1 = 1500 kg
  • initial speed of car = 35 miles/h

                               =\dfrac{35\times 1609.34}{3600}\ m/s

                               = 15.64 m/s

Initial kinetic energy of the car is given by,

k_1\ =\ \dfrac{1}{2}.m.v_1^2

       =\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule

       = 183606.46 J

  • Final velocity of car v2 = 70 miles/hour

                                      =\dfrac{70\times 1609.34}{3600}

                                      = 31.29 m/s

So, final kinetic energy of car is given by

k_2\ =\ \dfrac{1}{2}.m.v_2^2

        =\ \dfrac{1}{2}\times 1500\times (31.29)^2

        = 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}

=>\ k_2\ =\ 4k_1                      

Hence, the kinetic energy will increase by 4 times.

7 0
3 years ago
The table shows some values of a function of the form y = ax2 + bx + c.
natali 33 [55]

Answer:

Value of constant term c is (-4)

Step-by-step explanation:

The given table represents a function which is in the form of a quadratic equation,

y = ax² + bx + c

We choose three points (3, -10), (4, -16) and (5, -24) from the table and satisfy the equation to get the values of a, b, and c.

For point (3, -10)

-10 = a(3)² + 3b + c

9a + 3b + c = -10 -------(1)

For point (4, -16)

-16 = a(4)² + 4b + c

16a + 4b + c = -16 ------(2)

For point (5, -24)

-24 = a(5)² + 5b + c

25a + 5b + c = -24 -----(3)

Equation (1) - equation (2)

(9a + 3b + c) - (16a + 4b + c) = -10 + 16

-7a - b = 6

7a + b = -6 ------(4)

Equation (2) - equation (3)

(16a + 4b + c) - (25a + 5b + c) = -16 + 24

-9a - b = 8

9a + b = -8 -------(5)

Equation (4) - Equation (5)

(7a + b) - (9a + b) = -6 + 8

-2a = 2

a = -1

From equation (4),

-7(1) + b = -6

b = -6 + 7

b = 1

From equation (1)

9(-1) + 3(1) + c = -10

-9 + 3 + c = -10

c = -10 + 6

c = -4

Therefore, the value of constant term c is (-4).

5 0
3 years ago
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