we have that
x + 3y = 6 -------> first equation
2x − y = 10
x + 3y = 6-----> substract x both sides
-x+x+3y=6-x
3y=6-x-----> divide by 3 both sides
y=(6-x) /3
y=2-(x/3)
y=-(x/3)+2
therefore
the answer is
negative one thirdx + 2
Answer:
In step by step
Step-by-step explanation:
For #1, everything is perfect.
For #2, you wrote your functions out incorrectly, but your x input and y output are correct
#3 is a little messed up.
Your function is f(x)=-3x+1. Your given x's are -3, -1, 0, 1, 2, and 3. Plug all of these in.
1. f(-3)=-3(-3)+1
2. f(-1)=-3(-1)+1
3. f(0)=-3(0)+1
4. f(1)=-3(1)+1
5. f(2)=-3(2)+1
You have to cancel out the variables and then you plug it into a calculator.
Answer:
Step-by-step explanation:
C
Where is a n? please look at the question again!!
