Question

Picture attached below

Answer 1

Answer:

b

Step-by-step explanation:

Using the trigonometric identity

secx = $\frac{1}{cosx}$ and cos60° = $\frac{1}{2}$

Given

sec [ $sin^{-1}$ $\frac{\sqrt{3} }{2}$ ] ← evaluate bracket

= sec60°

= $\frac{1}{cos60}$

= $\frac{1}{\frac{1}{2} }$

= 2 → b