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Sidana [21]
3 years ago
9

H= -16t^2+16t+192 When will the ball hit the​ ground?

Mathematics
1 answer:
liubo4ka [24]3 years ago
6 0

Answer:

t = 4 s

Step-by-step explanation

We can infer the origin from the t⁰ term of the quadratic as being 192 feet above the ground. Initial velocity is  16 ft/s from the t¹ term, gravity is -32 ft/s² from the t² term

0 = -16t² + 16t + 192

0 = -t² + t + 12

0 = t² - t - 12

0 = (t - 4)(t + 3)

so either

t - 4 = 0

t = 4 s

or

t + 3 = 0

t = -3 s  which we ignore as it occurs before the ball is released.

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When you increase something by 40%, multiply the something by 1.4

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8 0
3 years ago
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Step-by-step explanation:

Substitute the value of the radius of the Earth into the formula given in the problem, where r is the radius, to obtain the surface area of the Earth:

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Threfore, the area of dry land is the following:

S_{land}=(0.292)(196,960,896miles^2)=57,512,581.63miles^2

8 0
3 years ago
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Thus since DE is equal to UV, then,

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3 years ago
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Answer:

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Step-by-step explanation:

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