How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
<h3>Density of the Neutron star</h3>
Density
ρ = m / V
Where:
ρ= density
m = mass of the planet 5.98 10²⁴ km
V =volume of the spherical layer
Volume of a sphere
Volume = 4/3 π r³
Mass = 1.5 = 1.5 1,991 10³⁰
Mass= 2.99 10³⁰ kg
Density:
ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]
ρ is = 7.13 10 17 kg / m³
V = 5.98 10²⁴ / 7.13 10¹⁷
V = 8,387 10⁶ m³
Thickness of the layer
V = 4π r² e
e = V / 4π r
e = 8,387 10⁶ / [4π (10 10³)²]
e = 6.67 10⁻³ m
Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
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The most likely answer I option 1
The following are true of mole ratio
- They are expressed as ratio of mass to molar mass
- It is measured in moles
<h3>How to calculate the mole ratio</h3>
The formula for calculating the mole ratio is expressed according to the formula shown:
Mole ratio is the ratio of the mass of a substance to the molar mass of the same substance.
To calculate the mole ratio
Mole = Mass(g)/molar mass(g/mol)
Hence the following are true of mole ratio
- They are expressed as ratio of mass to molar mass
- It is measured in moles
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- The population being all iPhone 4 users is True
- The 2% denote the sample statistic.
<h3>Sample statistic</h3>
This refers to the figures which are computed through the available data for
an item. Examples include:
The population being all iphone 4 user is true because it is the item that has
the data provided and is being talked
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