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allsm [11]
2 years ago
6

A prism has a height of 11.2 centimeters and an equilateral triangle for a base, where each base edge is 8 centimeters. find the

volume. round your answer to the nearest hundredth.
SAT
1 answer:
Mademuasel [1]2 years ago
4 0

The volume of the triangular prism with the given height and base dimensions to the nearest hundredth is 310.38cm³.

<h3>What is a triangular prism?</h3>

A triangular prism is simply a three-dimensional solid with three rectangular sides and two triangular bases.

The volume of an equilateral triangular prism is expressed as;

V = (√3/4) × a² × h

Given the data in the question;

  • Height h = 11.2cm
  • Sides a = 8cm
  • Volume V = ?

We substitute our values into the equation above.

V = (√3/4) × a² × h

V = (√3/4) × (8cm)² × 11.2cm

V = (√3/4) × 64cm² × 11.2cm

V = 310.38cm³

Therefore, the volume of the triangular prism with the given height and base dimensions to the nearest hundredth is 310.38cm³.

Learn more about triangular prism here: brainly.com/question/24046619

#SPJ1

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<h3><u>Ⲁⲛ⳽ⲱⲉⲅ:</u></h3>

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\quad\rule{300pt}{1pt}\quad

<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ :</u></h3>

We are given that a cylinder shaped bucket is used as a sand container . We have to find how much sand it can hold , which can be found by knowing the volume of cylindrical bucket .The volume of a cylinder is given by :

\quad\dashrightarrow\quad {\pmb{\sf {Volume = \pi r^2 h }}}

where,

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\quad\dashrightarrow\quad \sf {V =\pi r^2 h }

\quad\dashrightarrow\quad \sf { V = 3.14 \times 0.5^2 \times 2.5}

\quad\dashrightarrow\quad \sf {V = 3.14\times 0.5\times 0.5\times 2.5 }

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‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>bucket </u><u>can </u><u>hold </u><u>1</u><u>.</u><u>9</u><u>6</u><u> </u><u>feet³</u><u> </u><u>of </u><u>sand!</u>

\rule{350pt}{2pt}

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