There were 40 tourist class passengers and 12 first class passengers.
Explanation:
Let the number of passengers who booked for tourist class be
=
x
Then, number of passengers who booked for first class
=
52
−
x
According to question,
Total money paid = $25(tourist class)+$30(first class)
$
1360
=
$
25
(
x
)
+
$
30
(
52
−
x
)
1360
=
25
x
+
1560
−
30
x
1360
−
1560
=
25
x
−
30
x
−
200
=
−
5
x
x
=
−
200
−
5
x
=
40
So, there were 40 tourist class passengers.
Now first class passengers
=
52
−
x
=
52
−
40
=
12
∴
There were 40 tourist class passengers and 12 first class passengers.
As a check
Total money paid = $25(tourist class)+$30(first class)
R
H
S
=
$
25
(
40
)
+
$
30
(
12
)
$
1000
+
$
360
=
$
1360
L
H
S
=
$
1360
Hence verified.
Answer:
Step-by-step explanation:
Probability of winning a game = 0.34
a) Probability of winning two games simultaneously = .34 x .34 =.1156
b) Probability of winning 3 games in a row = .34³
c) Probability of winning three chess games in a row and failure in the fourth = .34³ x ( 1-.34)
c)
Answer:
55
Step-by-step explanation:
Combination will be used here as teams are a group.
So using combination:
<em>No. of combination of 'n' things taken 'r' at a time</em>
<em>
= 
</em>
here n = 11 ,
r = 9
11<em>C</em>9 <em>= 
= 
</em>
11<em>C</em>9<em> =</em><em> 55</em>
<em>Which are the possible 9 player starting lineups</em>
