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3 years ago

13

Using the digits 1 to 5 , Atmos one time, placed a digit in each box to create an expression which is the largest possible value

.

1 answer:

lukranit [14]3 years ago

7 0

Answer:

4^5+2x3

Step-by-step explanation:

4^5+2x3

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Solve for x in the diagram below

SVEN [57.7K]

Answer:

$x=6^o$

Step-by-step explanation:

we know that

$5x^o+(x+54)^o=90^o$ -----> by complementary angles

solve for x

$6x=90-54\\6x=36\\x=6^o$

3 0

3 years ago

What is the limit of cosine as x approaches infinity?

sesenic [268]

Does not exist, since the graph of cosine is continuous between the intervals [-1,1]. You do not know where it will be when it “reaches” infinity

6 0

4 years ago

Burt's grandparents started a savings account for him when he was born. They invested

SashulF [63]

Answer:

4594.76 USD will be in the account on Burt's 18th birthday.

Step-by-step explanation:

Since interest rate is constant in time, we can use the definition of composite interest to determine how much money will be on Burt's 18th birthday, that is:

$C = C_{o}\cdot \left(1+\frac{r}{100} \right)^{t}$ (1)

Where:

$C_{o}$ - Initial amount, measured in US dollars.

$C$ - Current amount, measured in US dollars.

$r$ - Annual interest rate, measured in percentage.

$t$ - Time, measured in years.

If we know that $C_{o} = 1250\,USD$ , $r = 7.5$ and $t = 18$ , then the money in the savings account on Burt's 18th birthday is:

$C = (1250\,USD)\cdot \left(1+\frac{7.5}{100} \right)^{18}$

$C = 4594.76\,USD$

4594.76 USD will be in the account on Burt's 18th birthday.

5 0

3 years ago

Put the functions, with their corresponding intervals, in order from least to greatest according to their average rates of chang

Svetllana [295]

Answer

Step-by-step explanation:

easy

8 0

2 years ago

Given that two sides of a triangle have sides 5 and 7, write the range of the lengths of the third side:

matrenka [14]

Answer:

Step-by-step explanation:

The two sides add up to 12. If the third "side" of the triangle is 12, then 5 and 7 will lie horizontally on 12.

So the maximum value must be less than 12. What's the smallest x could be?

well 5 + something must be > than 7. If they are not larger than 7, then 5 and something will lie on 7 just as it did before. So how big is something?

5 + y > 7

5 - 5 + y > 7 - 5

y > 2

So the range is 2 < x < 12

How else could you write this?

2 < x

x < 12 is one way.

6 0

3 years ago