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nikklg [1K]
2 years ago
13

Using the digits 1 to 5 , Atmos one time, placed a digit in each box to create an expression which is the largest possible value

.

Mathematics
1 answer:
lukranit [14]2 years ago
7 0

Answer:

4^5+2x3

Step-by-step explanation:

4^5+2x3

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invent three meaningful algebatric expressions of your own from the list of variables and enter them into the table below.write
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Answer:

49

Step-by-step explanation:

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The figure shows a parallelogram inside a rectangle outline: A parallelogram is shown within a rectangle. The length of the rect
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Answer=5/16 or 0.3125 feet

Step-by-step explanation:

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3 years ago
Which is a table of values for y = x - 6? I don't know how to solve functions
vladimir2022 [97]
I Have made a table for you. You start by making a table, <span>To graph with a table you simply pick numbers for </span>x<span> and solve for </span>y<span> by plugging </span>x<span> into the equation. This gives you the points to graph.</span>

4 0
3 years ago
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Which of the following is the product of the rational expressions shown below?
kotykmax [81]

Answer: OPTION D.

Step-by-step explanation:

You have the expressions given in the problem:

\frac{2}{2x+3}*\frac{9}{x}

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You must multiply the numerators of both expression and the denominators of both expression.

Keeping the above on mind, you obtain that the product is:

\frac{2*9}{(2x+3)x}

 \frac{18}{2x^{2}+3x}

3 0
3 years ago
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Im confused..I feel as if what I’m learning in class itself is not as difficult as the problems my teacher gives us to take home
RideAnS [48]
Ok, so remember that the derivitive of the position function is the velocty function and the derivitive of the velocity function is the accceleration function

x(t) is the positon function
so just take the derivitive of 3t/π +cos(t) twice
first derivitive is 3/π-sin(t)
2nd derivitive is -cos(t)
a(t)=-cos(t)

on the interval [π/2,5π/2) where does -cos(t)=1? or where does cos(t)=-1?
at t=π
so now plug that in for t in the position function to find the position at time t=π
x(π)=3(π)/π+cos(π)
x(π)=3-1
x(π)=2
so the position is 2







ok, that graph is the first derivitive of f(x)
the function f(x) is increaseing when the slope is positive
it is concave up when the 2nd derivitive of f(x) is positive

we are given f'(x), the derivitive of f(x)
we want to find where it is increasing AND where it is concave down

it is increasing when the derivitive is positive, so just find where the graph is positive (that's about from -2 to 4)

it is concave down when the second derivitive (aka derivitive of the first derivitive aka slope of the first derivitive) is negative
where is the slope negative?
from about x=0 to x=2
and that's in our range of being increasing
so the interval is (0,2)
4 0
3 years ago
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