Not sure if you can do this but it sounds like a velocity/time/distance equation.
d=vt
v=d/t
t=d/v
70 w/m = t
15 pages - 350 w/p
She can type 70 words per minute (w/m). There are 350 words per page (w/p). She needs 15 pages. So first you have to find how many words she can type in one hour. 60 minutes in an hour, she can type 70 w/p.
60x70=4,200 words per hour (w/h).
Next you should find out how many words on 15 pages total.
350x15= 5,250.
I would put 4,200/5,250 as a fraction to gage how much she has left. She has most of it done already in ONE HOUR. Reduced, she has done 4/5s of the essay. Now you just need to get 1/5 of 5250, which is 1050.
She needs to do 1050 words. If one minute is 70, do 1050/70 which is 15.
The answer is 1 hour and 15 minutes.
I think... ;)
Please list the answer options. I can solve but I need the answer options.
Answer:
TRUE
Step-by-step explanation:
TRUE
a_1 = 2
a_n = 2*(an_1)
if we start with 2, we would get
a_2 = 2*(a_1) = 2*(2) = 4
a_3 = 2*(a_2) = 2*(4) = 8
a_4 = 2*(a_3) = 2*(8) = 16
a_5 = 2*(a_4) = 2*(16) = 32
.
.
.
and so on
Although there i no triangle given as the question requires, I am still going to answer because I understand it.
ABC is a right angled triangle. The triangle is 90° at C.
The trigonometric ratio sine is given by, sine = opposite/hypotenuse .
Cosine = adjacent/hypotenuse
So therefore, Sin A = 24/30
= 4/5
Cos A = 18/30
= 3/5
Answer:
Probability of a sample that contains exactly two defective parts is .0037 or .37%
Step-by-step explanation:
As we know if P is the probability of achieving k results in n trials then probability formula is P = 
In this formula n = number of trials
k = number of success
(n-k) = number of failures
p = probability of success in one trial
q = (1-p) = probability of failure in one trial
In this sum n = 5
k = 2
number failures (n-k) = (5-2) = 3
p = 2% which can be written as .02
q = 98% Which can be written as .98
Now putting these values in the formula
P = 
P = 
= 5×4×3×2×1/3×2×1×2×1
= 5×2 =10
P = 10×(.02)²×(.98)³
= .0037 or .37%
