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viktelen [127]
2 years ago
6

A line has a slope of 7 and a y-intercept of -2

Mathematics
1 answer:
geniusboy [140]2 years ago
5 0

Answer: it's -1

Step-by-step explanation: Hope this helps

Can I have brainliest?

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Answer:

The Answer is B

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What is the solution to an equation /
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Idk what u mean?

Step-by-step explanation:

but i searched it up and here are my results

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true. For equations having one unknown, raised to a single power, two fundamental rules of algebra, including the additive property and the multiplicative property, are used to determine its solutions.Mar 20, 2020

email me if it helps

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3 years ago
What is the summation notation for the series? 200+175+150+125+___+(-300)
ozzi
  21
  E    (225-25n)
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So its D.
5 0
3 years ago
Read 2 more answers
Using your knowledge of exponential and logarithmic functions and properties, what is the intensity of a fire alarm that has a s
Ierofanga [76]

Option B:

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Solution:

Given sound level = 120 decibel

To find the intensity of a fire alarm:

$\beta=10\log\left(\frac{I}{I_0} \right)

where I_0=1\times10^{-12}\ \text {watts}/ \text m^2}

Step 1: First divide the decibel level by 10.

120 ÷ 10 = 12

Step 2: Use that value in the exponent of the ratio with base 10.

10^{12}

Step 3: Use that power of twelve to find the intensity in Watts per square meter.

$10^{12}=\left(\frac{I}{I_0} \right)

$10^{12}=\left(\frac{I}{1\times10^{-12}\ \text {watts}/ \text m^2} \right)

Now, do the cross multiplication,

I=10^{12}\times1\times\ 10^{-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{12-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{0} \ \text {watts}/ \text m^2}

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Option B is the correct answer.

Hence I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}.

5 0
3 years ago
pllllllls I need help right triangle and trigonometry special right triangles find the value of each variable​
yanalaym [24]

\huge {\mathfrak{Answer :  }}

we know,

\boxed{\cos( \theta)  =  \dfrac{base}{hypotenuse}}

so,

  • \cos(30)  =  \dfrac{24}{x}

  • \dfrac{ \sqrt{3} }{2}  =  \dfrac{24}{x}

  • x =  \dfrac{24 \times 2}{ \sqrt{3} }

  • x = 8 \sqrt{3}  \times 2

  • x = 16 \sqrt{3}

now,

\boxed{ \tan( \theta) =  \frac{perpendcular}{base}  }

  • \tan(30)  =  \dfrac{y}{24}

  • \dfrac{1}{ \sqrt{3} }  =  \dfrac{y}{24}

  • y =   \dfrac{24}{ \sqrt{3} }

  • y = 8 \sqrt{3}
6 0
2 years ago
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