Using the relation between velocity, distance and time, it is found that:
- The rate of the plane in still air is of 140 mph.
- The rate of the wind is of 40 mph.
<h3>What is the
relation between velocity, distance and time?</h3>
Velocity is <u>distance divided by time</u>, that is:

A plane traveling with the wind travels 900 miles in 5 hours, hence:


The return trip is against the wind and takes 9 hours, hence:


From the first equation, we have that:
![v_w = 180 - v_a{/tex]Replacing on the second:[tex]v_a - v_w = 100](https://tex.z-dn.net/?f=v_w%20%3D%20180%20-%20v_a%7B%2Ftex%5D%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EReplacing%20%3C%2Fstrong%3Eon%20the%20second%3A%3C%2Fp%3E%3Cp%3E%5Btex%5Dv_a%20-%20v_w%20%3D%20100)



[tex]v_w = 180 - 140 = 40{/tex]
Hence:
- The rate of the plane in still air is of 140 mph.
- The rate of the wind is of 40 mph.
More can be learned about the relation between velocity, distance and time at brainly.com/question/24316569
Answer:
3.4
Step-by-step explanation:
2/5 as a decimal is 0.4, and we can add 3 to it, getting 3.4
Reflected across the x-axis, the function becomes
... g(x) = -f(x) = -20 +4x
This models the situation in which the car is driving in reverse, is accelerating (velocity is becoming less negative), and comes to a stop in 5 seconds.
Of the choices offered, the best seems to be ...
... b. the car immediately begins to accelerate at the same rate it had previously decelerated.
4.312, 4.316, 4.32, 4.5
I hope this helps ^W^ have a great day!