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tigry1 [53]
3 years ago
13

5.) Mother went to the supermarket. She bought 1.8 kg of chicken at Php120.50 a kilo

Mathematics
1 answer:
lutik1710 [3]3 years ago
8 0

Answer:

1.8×120.50, and u shd get the ans

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Adam spent $3.42 on orange juice. It costs .12 per ounce. How many did Adam buy?
SIZIF [17.4K]
Hi, 


 I would say that the answer is 28, but it still doesn't add up because when you multiply 12 by 28 you get $3.36 which isn't enough to meet his total, so I tried multiplying 12 by 29 and I got $3.48, which is six cents over his total. So I'm sorry if it is wrong I tried to help to my best ability.

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What does x is greater than 5 mean
kotegsom [21]

Answer:

That  x is any number  bigger that 5 so 6 plus

Step-by-step explanation:

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4 years ago
Solve for x.
konstantin123 [22]
5x/7 - 5 = 50 is 4. x = 77
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3 years ago
The pH of a solution is measured eight times by one operator using the same instrument. She obtains the following data: 7.15, 7.
Nikolay [14]

Answer:

(a)7.185

(b)0.000371

(c) 0.019

(d)Sample variance and Sample standard deviation

Step-by-step explanation:

We are given the following sample data.

7.15, 7.20, 7.18, 7.19, 7.21, 7.20, 7.17, 7.18.

(a) Calculate the sample mean. Round your answer to 3 decimal places.

The formula for sample mean =

Sum of terms/Number of terms

= 7.15 + 7.20+ 7.18+7.19+7.21+7.20+7.17+ 7.18/8

= 57.48/8

= 7.185

(b) Calculate the sample variance. Round your answer to 6 decimal places.

The formula for sample Variance =

(x - mean)²/n - 1

n = 8

Sample variance = (7.15 - 7.185)² + (7.20-

7.185)²+ (7.18 -7.185)² + (7.19 -7.185)² + (7.21 - 7.185)² + (7.20 - 7.185)² + (7.17 - 7.185)² + (7.18 - 7.185)² /8 - 1

= 0.001225 + 0.000225+ 0.000025+ 0.000025 + 0.000625 + 0.000225 + 0.000225 + 0.000025/7

= 0.0026/7

= 0.000371428571

Approximately to 6 decimal places = 0.000371

(c) Calculate the sample standard deviation. Round your answer to 3 decimal places.

The formula for Sample Standard Deviation = √Sample variance

= √0.000371428571

= 0.01927248223

To 3 decimal places = 0.019

(d) Which of the following are potential major sources of variability in the experiment

Sample variance

Sample standard deviation

4 0
3 years ago
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