Please help please please pleseeeeeeeee

Anybody know the answer to this -20=-4+8h ?

kompoz [17]

Answer:{h^2+4-(8*h-3)=0}using 3 different

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

Jillana begins to solve a linear equation that results in a variable expression set equal to the same variable expression. Which

DanielleElmas [232]

Answer: that the variable can be any number.

Step-by-step explanation:

So we have a linear equation and we end with a relation of the way:

x = x

an example can be if we have:

2*x + 4 = 2*(x + 2)

if you solve that, you will end with a relationship x = x

this means that any value of x will made that equality true.

so x can be any number.

6 0

3 years ago

Declan needs euros to go on holiday. He can buy 46 euros for £40. How much will 805 euros cost at the same rate?

kobusy [5.1K]

Answer:

700 pounds

Step-by-step explanation:

if 46 euros cost 40 pounds

then 805 euros will cost 805 multiplied 40

whatever answer you get divide it by 46

6 0

4 years ago

Ms.Vogel is riding the stationery bike at the gym. She completes 61 7/8 wheel rotations every 1/2 minute. What is ms. Vogels uni

Drupady [299]

Ms. Vogels unit rate is $123\frac{3}{4}$ rotations per minute.

Step-by-step explanation:

Given,

Rotations completed in 1/2 minute = $61\frac{7}{8}=\frac{495}{8}\ rotations$

$\frac{1}{2}\ minute=\frac{495}{8}\ rotations$

For unit rate, we will multiply both sides with 2

$2*\frac{1}{2}\ minutes=\frac{495}{8}*2\\\\1\ minute = \frac{495}{4}\ rotations\\\\ 1\ minute = 123\frac{3}{4}\ rotations$

Ms. Vogels unit rate is $123\frac{3}{4}$ rotations per minute.

Keywords: unit rate, fraction

Learn more about fractions at:

#LearnwithBrainly

4 0

4 years ago

3/2 x 4/3 x 5/4… x 2006/2005

Lady_Fox [76]

Answer:

1003

Step-by-step explanation:

The problem is a classic example of a telescoping series of products, a series in which each term is represented in a certain form such that the multiplication of most of the terms results in a massive cancelation of subsequent terms within the numerators and denominators of the series.

The simplest form of a telescoping product $a_{k} \ = \ \displaystyle\frac{t_{k}}{t_{k+1}}$ , in which the products of <em>n</em> terms is

$a_{1} \ \times \ a_{2} \ \times \ a_{3} \ \times \ \cdots \times \ a_{n-1} \ \times \ a_{n} \ = \ \displaystyle\frac{t_{1}}{t_{2}} \ \times \ \displaystyle\frac{t_{2}}{t_{3}} \ \times \ \displaystyle\frac{t_{3}}{t_{4}} \ \times \ \cdots \ \times \ \displaystyle\frac{t_{n-1}}{t_{n}} \ \times \ \displaystyle\frac{t_{n}}{t_{n+1}} \\ \\ \-\hspace{5.55cm} = \ \displaystyle\frac{t_{1}}{t_{n+1}}.$ .

In this particular case, $t_{1} \ = \ 2$ , $t_{2} \ = \ 3$ , $t_{3} \ = \ 4$ , ..... , in which each term follows a recursive formula of $t_{n+1} \ = \ t_{n} \ + \ 1$ . Therefore,

$\displaystyle\frac{t_{2}}{t_{1}} \times \displaystyle\frac{t_{3}}{t_{2}} \times \displaystyle\frac{t_{4}}{t_{3}} \times \cdots \times \displaystyle\frac{t_{n}}{t_{n-1}} \times \displaystyle\frac{t_{n+1}}{t_{n}} \ = \ \displaystyle\frac{3}{2} \times \displaystyle\frac{4}{3} \times \displaystyle\frac{5}{4} \times \cdots \times \displaystyle\frac{2005}{2004} \times \displaystyle\frac{2006}{2005} \\ \\ \-\hspace{5.95cm} = \ \displaystyle\frac{2006}{2} \\ \\ \-\hspace{5.95cm} = 1003$

6 0

3 years ago