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VARVARA [1.3K]
3 years ago
6

I NEED HELP ASAP!!!!!

Mathematics
2 answers:
Anna007 [38]3 years ago
7 0
Hopefully this can help

marshall27 [118]3 years ago
4 0

Answer:

15 weeks

Step-by-step explanation:

You divide $174 to $12 to get the number of weeks:

174/12 = 14.5

Because we are talking about how many weeks, we round this number to 15. Hope this works :)

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The body of a person who weighs 50 kilograms contains around 2 × 102 grams of sodium chloride. How much sodium chloride is conta
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I'm not sure but I.think it's C
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3 years ago
A bag contains 5 red, 4 green, and 3 blue marbles.
Mila [183]

Answer:

1/12

Step-by-step explanation:

I just did this question and it was right :)

Thought I would help since I couldn't find the answer

8 0
3 years ago
18x - 432 - 18x - 6x² +144
ArbitrLikvidat [17]

Answer:

-6x^2-288

Step-by-step explanation:

18x - 432 - 18x - 6x² +144

Combine like terms

-6x^2+18x-18x-432+144

-6x^2-288

7 0
3 years ago
What is the y-intercept for the equation y = 11x + 1?
Dafna11 [192]

Answer:

(0, 1)

Step-by-step explanation:

<u>Step 1:  Determine the y-intercept</u>

Using the slope intercept form, we know that the equation is y = mx + b where m is the slope and b is the y-intercept.  Therefore, looking at our equation, we can tell that b is 1 therefore the y-intercept is (0, 1)

Answer: (0, 1)

5 0
2 years ago
Read 2 more answers
The length of pregnancy isn’t always the same. In pigs, the length of pregnancies varies according to a normal distribution with
Nesterboy [21]

a. percent of pig pregnancies that are longer than 106 days

Since we have a normal distribution here and the average number of days is 106, we can say that 50% of the pig pregnancies are longer than 106 days.

b. percent of pig pregnancies that are shorter than 111 days

To get the percentage, we will have to convert x = 111 days into a z-score first. The formula is:

z=\frac{x-\mu}{\sigma}

where x = raw data, μ = population mean, and σ = population SD.

Since these 3 pieces of information are already given in the question, let's plug them into the equation above.

z=\frac{111-106}{5}=\frac{5}{5}=1\sigma

Therefore, 111 days is located 1 standard deviation to the right of the mean.

To find the percentage of pig pregnancies shorter than 111 days, we need to find the area covered to the left of 1 SD.

To find the area covered to the left of 1SD, we need to use the standard normal distribution table.

Based on the table, the area covered to the left of 1SD is 0.8413. Multiplying the area by 100, we get 84.13. Therefore, 84.13% of the pig pregnancies are shorter than 111 days.

5 0
1 year ago
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