Find the sum. (–7b + 8c) – (12a + 14) + (5a + 5b)
2 answers:
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Explanation : If 66 is a factor of this unknown value, then 22 must be as well considering that 22 is a factor off 66. Let's say that this large value is 330. It is a multiple of 66, as 66 5 = 330. At the same time 22
15 = 330, so 330 is a multiple of 22 as well - or vice versa, 12 is a factor of 330.
We can also tell that 15, 22 fit into 330 through another approach. 22 3 = 66, and 66
5 = 330, so 5
3 = 15 - the same value. This proves that 22 will always be a factor of a value that is the factor of 66.