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morpeh [17]
3 years ago
13

The 24 students in ms. lees class each collected an average of 18 cans for recycling. then 21 students in mr. galvez's class eac

h collected an average of 25 cans for recycling. how many more cans were collected by mr. galvez's class than ms. lee's class
Mathematics
1 answer:
belka [17]3 years ago
7 0

This can be solve by using the average cans of each student collected and muliply it by the total students. Since for ms. Lee has 24 students and each student collected 18 cans on average, so the total can her class collected on average is 432 cans. For mr galveshas 21 students and collected 25 can per syudents on average, so the total is 525 cans. So 525 – 432 = 93 more cans the class of mr galvez collected

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Using a geometric sequence, it is found that:

a) For the first 5 weeks, the numbers are: 2, 4, 8, 16, 32

b) Hence some of the volunteers can stop recruiting new volunteers during the 7th week.

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

a_n = a_1q^{n-1}

In which a_1 is the first term.

For this problem, on the first week there are 2 people, and since each new people involve two more, the common ratio is of 2, hence the parameters for the geometric sequence are:

a_1 = 2, q = 2

Hence the number of people after n weeks is:

a_n = 2 \times 2^{n - 1}

For the first 5 weeks, the numbers are:

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There will be 150 volunteers when a_n = 150, hence:

2 \times 2^{n - 1} = 150

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The above is because 2^7 = 128 and 2^8 = 256, and 128 < 150 < 256.

Hence some of the volunteers can stop recruiting new volunteers during the 7th week.

More can be learned about geometric sequences at brainly.com/question/11847927

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