Question

A rock dropped on the moon will increase its speed from 0 m/s (its starting

Answer 1

Hello!

The answer is:

The correct option is the option D

$g=1.63\frac{m}{s^{2}}$

Why?

To calculate the acceleration, we need to use the following formula that involves the given information (initial speed, final speed, and time).

We need to use the following free fall equation:

$V_{f}=V_{o}-g*t$

Where:

$V_{f}$ is the final speed.

$V_{o}$ is the initial speed.

g is the acceleration due to gravity.

t is the time.

We are given the following information:

$V_{f}=8.15\frac{m}{s}$

$V_{o}=0\frac{m}{s}$

$t=5seconds$

Then, using the formula to isolate the acceleration, we have:

$V_{f}=V_{o}-g*t$

$V_{f}=V_{o}-g*t\\\\g*t=V_{o}-V_{f}\\\\g=\frac{V_{o}-V_{f}}{t}$

Now, substituting we have:

$g=\frac{V_{o}-V_{f}}{t}$

$g=\frac{0-8.15\frac{m}{s}}{5seconds}=-1.63\frac{m}{s^{2}}$

Therefore, since we are looking for a magnitude, we have that the obtained value will be positive, so:

$g=1.63\frac{m}{s^{2}}$

Hence, the correct option is the option D

$g=1.63\frac{m}{s^{2}}$

Have a nice day!