let's firstly convert the decimal to a fraction, namely a rational.
so we have one decimal, thus let's use 1 zero at the denominator and lose the dot on the numerator.
so then, what rationals are between -8/5 and +8/5? well, a huge amount hmmm let's pick two.
![\bf \boxed{-\cfrac{8}{5}}\rule[0.35em]{9.5em}{0.25pt}~~-\cfrac{3}{5}~~\rule[0.35em]{2em}{0.25pt}0\rule[0.35em]{10em}{0.25pt}~~\cfrac{6}{5}~~\rule[0.35em]{2.5em}{0.25pt}\boxed{\cfrac{8}{5}}](https://tex.z-dn.net/?f=%5Cbf%20%5Cboxed%7B-%5Ccfrac%7B8%7D%7B5%7D%7D%5Crule%5B0.35em%5D%7B9.5em%7D%7B0.25pt%7D~~-%5Ccfrac%7B3%7D%7B5%7D~~%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D0%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D~~%5Ccfrac%7B6%7D%7B5%7D~~%5Crule%5B0.35em%5D%7B2.5em%7D%7B0.25pt%7D%5Cboxed%7B%5Ccfrac%7B8%7D%7B5%7D%7D)
X^2 - 9....factor
= x^2 - 3^2
= (x+3)(x-3)
Answer:
v=26.41 m/s
Step-by-step explanation:
From the Newtons laws of motions, we sew that x= (2v₁²sin∅os∅)/g where x is the horizontal distance v is the initial speed and ∅ is the launch angle.
From trigonometry we see that 2 sin∅cos∅=sin 2∅
Therefore, x=(v²sin2∅)/g
x=22m
∅=9°
g=9.8m/s²
22m=v²×sin(2×9)/(9.8m/s²)
v²=(22×9.8)/(sin 18)
v²=697.696
v=√697.696
v=26.41 m/s
So to get the answer you multiply 48 by 1.15 and you get 55.2
Chung's go-kart can travel 55.2 miles on 1.15 gallons of gas.
