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tresset_1 [31]
3 years ago
6

What do the two lines mean on the sides of the figure? Need help

Mathematics
2 answers:
AnnyKZ [126]3 years ago
8 0

Answer:

May i know what figure you are talking about.

Step-by-step explanation:

Vikentia [17]3 years ago
8 0
There is no picture so we have no idea what ur talking abou
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Maybe a little more point will make you help me
Natasha_Volkova [10]

Answer:

SA = 76 yd²

Step-by-step explanation:

Use the formula given:

  • SA = 2(4)(2) + 2(4)(5) + 2(2)(5)
  • SA = 16 + 40 + 20
  • SA = 76

The units are yards²

SA = 76yd²

-Chetan K

5 0
3 years ago
Read 2 more answers
What is the answer to 56x76
Simora [160]

Answer:  The answer is 4,256

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
In the following system of equations, what would you do to eliminate x? 2x + 4y = 10 x - 3y = 12
Anvisha [2.4K]
2x +4y =10x-3y =12

2x +4y =12 -----eq. 1

10x-3y =12 -------eq.2


2x =12 -4y [using eq. 1]
x = (12-4y)/ 2
= 6 -2y

Now, substitute the value of x in eq. 2
10 (6-2y)-3y =10
60 -20y -3y =10
-23 y = 10 -60
y = -50 / -23
y = 50/23


Now, substitute this value of y in any equations given above

10 x-3 (50/23) =12
10x - (150/23)= 12
x= 426/230
8 0
4 years ago
Write 504 as a product of powers of its prime factor
34kurt
504 = 2 x 2 x 2 x 3 x 3  x 7
8 0
4 years ago
A car, originally valued at 70,000 in 2006 depreciates exponentially at a rate of 4% each year. Round the expected value of the
lora16 [44]

Answer:

$42,890

Step-by-step explanation:

The standard form for an exponential equation is

y=a(b)^x

where a is the initial amount value and b is the growth rate or decay rate and t is the time in years.  Since we are dealing with money amounts AND this is a decay problem, we can rewrite accordingly:

A(t)=a(1-r)^t

where A(t) is the amount after the depreciation occurs, r is the interest rate in decimal form, and t is the time in years.  We know the initial amount (70,000) and the interest rate (.04), but we need to figure out what t is.  If the car was bought in 2006 and we want its value in 2018, a total o 12 years has gone by.  Therefore, our equation becomes:

A(t)=70,000(1-.04)^{12} or, after some simplification:

A(t)=70,000(.96)^{12}

First rais .96 to the 12th power to get

A(t) = 70,000(.6127097573)

and then multiply.

A(t) = $42,890

8 0
3 years ago
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