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jekas [21]
3 years ago
14

Simplify the ratio 16.8 to 11.2. is​

Mathematics
1 answer:
Ganezh [65]3 years ago
6 0

Answer:

5.7

Step-by-step explanation:

Im not so sure if this is the correct answer but i hope if helps! <3

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Find the value of x (4x+7) 97 (17x+13)
zysi [14]

Answer:

4x^2 +1656x + 1261

Step-by-step explanation:

X multiply by 4x is 4x^2 (4x squared)

x multiply by 7 is 7x

4x^2+7x

97 x 17x is 1649x

97 x 13 is 1261

1649x+1261

4x^2 + 7x + 1649x + 1261

1649x + 7x is 1656x

4x^2 +1656x + 1261

4 0
3 years ago
Read 2 more answers
The sum of four consecutive odd numbers is 80 find the number
Setler [38]

Answer:

Let the numbers are

x, (x+2), (x-2) and (x+4)

Step-by-step explanation:

x + x +2 +x - 2+x+4 = 80

4x +4 = 80

4x =80-44x = 76

4x = 76

x = 76/4

x = 19x

x=19

(x+2) =19+2=21

(x-2) = 19-2=17

(x+4)=(19+4)=23

hope it helps

mark me brainliest pls

4 0
3 years ago
Write the statement below as a math expression
lukranit [14]
D. 2(n-8)

The difference of a number and eight is separate from being multiplied by 2 which is why you would use parenthesis.
3 0
3 years ago
Hewwo!
ella [17]

Answer:

See Below.

Step-by-step explanation:

Please refer to the diagram below.

We are given that O is the center of the circle, and chords MN and RS are intersected a P. OP is the bisector of ∠MPR. And we want to prove that MN = RS.

We will construct segments OK and OJ such that it perpendicularly bisects MN and RS.

Since OP bisects ∠MPR, it follows that:

\displaystyle \angle JPO\cong \angle KPO

And since OK and OJ are perpendicular bisectors:

m\angle OKP=90^\circ \text{ and } m\angle OJP=90^\circ

Therefore:

\angle OKP\cong \angle OJP

By the Reflexive Property:

OP\cong OP

Therefore:

\Delta OKP\cong \Delta OJP

By AAS Congruence.

Hence:

OK\cong OJ

By CPCTC.

Recall that congruent chords are equidistant from the center.

Thus, by converse, chords that are equidistant from the center are congruent.

Therefore:

MN\cong RS

7 0
3 years ago
Read 2 more answers
Please help me this is so hard
Anastaziya [24]

Answer:

1. 3    36

      2          18

           2             9

                  2            3

The Prime Factorization is:

2 x 2 x 3 x 3

In Exponential Form:

22 x 32

CSV Format:

2, 2, 3, 3

All Factors of 36:

1, 2, 3, 4, 6, 9, 12, 18, 36

2. 7      42

      2         21

          3         7

_______________________

The Prime Factorization is:

2 x 3 x 7

In Exponential Form:

21 x 31 x 71

CSV Format:

2, 3, 7

All Factors of 42:

1, 2, 3, 6, 7, 14, 21, 42

__________________________________

3.  48

2          24

 2              12

     2               6

          2              3

The Prime Factorization is:

2 x 2 x 2 x 2 x 3

In Exponential Form:

24 x 31

CSV Format:

2, 2, 2, 2, 3

All Factors of 48:

1, 2, 3, 4, 6, 8, 12, 16, 24, 48

_________________________________

4.   27

 3        9

    3        3

The Prime Factorization is:

3 x 3 x 3

In Exponential Form:

3^3

CSV Format:

3, 3, 3

All Factors of 27:

1, 3, 9, 27

_________________________________________________

5. The Prime Factorization is:

2 x 2 x 11

In Exponential Form:

22 x 111

CSV Format:

2, 2, 11

All Factors of 44:

1, 2, 4, 11, 22, 44

__________________

6. The Prime Factorization is:

5 x 5 x 5

In Exponential Form:

5^3

CSV Format:

5, 5, 5

All Factors of 125:

1, 5, 25, 125

__________________________________

7. The Prime Factorization is:

5 x 17

In Exponential Form:

51 x 171

CSV Format:

5, 17

All Factors of 85:

1, 5, 17, 85

_________________________________

8. The Prime Factorization is:

3 x 13

In Exponential Form:

31 x 131

CSV Format:

3, 13

All Factors of 39:

1, 3, 13, 39

Step-by-step explanation:

5 0
3 years ago
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