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forsale [732]
2 years ago
11

The sum of four consecutive odd numbers is 80 find the number

Mathematics
1 answer:
Setler [38]2 years ago
4 0

Answer:

Let the numbers are

x, (x+2), (x-2) and (x+4)

Step-by-step explanation:

x + x +2 +x - 2+x+4 = 80

4x +4 = 80

4x =80-44x = 76

4x = 76

x = 76/4

x = 19x

x=19

(x+2) =19+2=21

(x-2) = 19-2=17

(x+4)=(19+4)=23

hope it helps

mark me brainliest pls

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The freezing point of a certain liquid is -7F . Another liquid freezes at -12F . What is the difference between the absolute val
melamori03 [73]

Answer:

Step-by-step explanation:

5

8 0
2 years ago
Please someone solve this, this is my third time reposting this question so yea please be quick
egoroff_w [7]

Answer:

Step-by-step explanation:

to calculate mean add all the entries in a week ,then divide by 7(the number of days)

i give you hint

mean for week 1=(52+65+...   +60)/7

8 0
2 years ago
Given the domain (-2,2,4) what is the range for the relation 3x-y=3
Bumek [7]

Answer:

Given the domain, the range for 3x-y = 3 is {-9, 6, 9}

Step-by-step explanation:

First you have to put the relation in terms of y ⇒ 3x - y = 3⇒ 3x -3 = y

⇒ y = 3x - 3.

Then you replace the values indicated by the domain to find their "y" values (the ones that constitute the range).

f(-2) = -9

f(2) = 6

f(4) = 9.

Finally, the range for the given domain is {-9, 6, 9}

3 0
3 years ago
Change y-7=m(x-4) to standard form
Ivan

Answer:

  mx -y = 4m -7

Step-by-step explanation:

Standard form is ...

  ax +by = c

where a, b, c are mutually prime integers and a > 0.

If we assume m > 0, then we need to collect the variable terms on the right side of the equation, so the coefficient of x will be positive.

  y -7 = mx -4m . . . . eliminate parentheses

  -7 = mx -y -4m . . . . subtract y

  4m -7 = mx -y . . . . . add 4m

  mx -y = 4m -7 . . . . . . standard form

4 0
2 years ago
Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon
Lisa [10]

Answer:

2.62 seconds

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> he height of the ball, in feet

we have

h(t)=-16t^2+40t+5

we know that

When the ball hits the ground, the height is equal to zero

so

-16t^2+40t+5=0

The formula to solve a quadratic equation of the form

at^{2} +bt+c=0

is equal to

t=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^2+40t+5=0

so

a=-16\\b=40\\c=5

substitute in the formula

t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}

t=\frac{-40\pm\sqrt{1,920}} {-32}

t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec

t=\frac{-40-\sqrt{1,920}} {-32}=2.62\ sec

therefore

The solution  is t=2.62 seconds

4 0
2 years ago
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