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Sladkaya [172]
3 years ago
14

4c = 3c + 4

Mathematics
1 answer:
svetlana [45]3 years ago
6 0

Answer:

c = 4

See explanation

Step-by-step explanation:

Given:

4c = 3c - 4

Your calculation:

4c = 3c + 4

4c = 4 - 3c

4c = 1c

c = 4/1

c= 4

Correct calculation:

4c = 3c + 4

Collect like terms by subtracting 3c from both sides

4c - 3c = 3c + 4 - 3c

c = 4

Check:

4c = 3c + 4

4(4) = 3(4) + 4

16 = 12 + 4

16 = 16

Therefore,

Your final answer is correct but your method of calculation is not correct

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Solve for b2 in A = 1/2 h(b1+b2), if A = 16, h = 4, and b1 = 3. 16= 1/2* 4(3+b2) =6+2b2 or, b2= [16-6]/2= 5
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Assuming you are referring to the area of a "trapezoid"; in which one calculates the Area, "A", as follows:
________________________
<span> A = 1/2* h(b1+b2) ;

in which: A = Area = 16 (given); 
               h = height = 4 (given);
               b1 = length of one of the two bases = 3 (given);
               b2 = length of the other of the two bases = ? (what we want to solve                                                                                            for) ;
______________________________________________________
Using the formula: </span>A = 1/2 h(b1+b2) ;
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Let us plug in our known values:
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 →  16 = (1/2) * 4*(3 + b2) ;  → Solve for "b2".
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 →Note: On the "right-hand side" on this equation: "(1/2)*(4) = 2 ." 
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 → 16 =   2*(3 + b2) ;  → Solve for "b2".
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We can divide EACH side of the equation by "2"; to cancel the "2" on the "right-hand side" of the equation:
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 → Rewrite as: 8 = 3 + b2;
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____________________
b2= [16-6]/2= 5 ; as this is the only answer choice that has: "b2 = 5".
<span>_________________________________________

As far getting "</span>b2 = 5"  from: "b2= [16-6]/2= 5"; (as mentioned in the answer choice), we need simply to approach the problem in a slightly different manner.  Let us do so, as follows:
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