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skelet666 [1.2K]
3 years ago
10

I dont understand how to solve a+5 ​

Mathematics
1 answer:
Ket [755]3 years ago
4 0

Answer:

5a

Not sure if this is correct !

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(−5)3x7(yz)4 / (3)2x2y8z2
g100num [7]

Answer:

\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}

Step-by-step explanation:

Given:

The expression to simplify is given as:

\frac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}

In order to simplify this, we have to use the law of indices.

1. (ab)^m=a^mb^m

So, (yz)^4=y^4z^4

Substitute this value in the above expression. This gives,

=\dfrac{(-5)3x^7y^4z^4}{(3)2x^2y^8z^2}\\\\\\=\dfrac{-15x^7y^4z^4}{6x^2y^8z^2}......(-5\times 3=15\ and\ 3\times 2=6)

Now, we use another law of indices.

2. \frac{a^m}{a^n}=a^{m-n}

So,  \frac{x^7}{x^2}=x^{7-2}=x^5,\frac{y^4}{y^8}=y^{4-8}=y^{-4}, \frac{z^4}{z^2}=z^{4-2}=z^2

Substitute these values in the above expression. This gives,

=\frac{-15}{6}\times x^5\times y^{-4}\times z^2\\\\=\frac{-5x^5y^{-4}z^2}{2}

Finally, we further simplify it using the law a^{-m}=\frac{1}{a^m}

So, y^{-4}=\frac{1}{y^4}

Therefore, the given expression is simplified as:

\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}

5 0
3 years ago
What kinetic energy has a 4kg shootput thrown with a velocity of 12m/s
Tamiku [17]

Answer:

288J

Step-by-step explanation:

recall the formula for kinetic energy

KE = (1/2) mv²

where m is the mass (= 4kg)  and v is the velocity(=12 m/s)

hence

KE = (1/2) (4)(12)² = 288J

7 0
3 years ago
Read 2 more answers
Can anyone help me with this please???
yanalaym [24]
Triangle = 3, Square = -1, Star = 5
8 0
3 years ago
Whoever answers this correctly gets brainlist!
Gnoma [55]

Answer:

5.  3/10

6.  7/12

7.   7/8

8.   4/3

Step-by-step explanation: Hope this helps!

7 0
3 years ago
Read 2 more answers
Given: f(x) = 2x + 5, match the inputs with their outputs.
bekas [8.4K]
Yeah the answer is number 5
3 0
3 years ago
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