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2 years ago

6

Can someone help me out with this angles triangle problem

1 answer:

postnew [5]2 years ago

6 0

Answer:

ΔEHG và ΔFKG đồng dạng

Mà GH/GK=3/5

=> EG/FG=3/5

=> KG=5EG/3

Mà EG+KG=32

=>EG+5EG/3=32

=> EG=12

Step-by-step explanation:

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Eduardwww [97]

9514 1404 393

Answer:

1. HA is equivalent to AAS when the triangle is a right triangle.

2. AM = BM, so the triangles are congruent by HL. CPCTC

3. The triangles are congruent by HL. CPCTC

Step-by-step explanation:

1. The acute angle of the triangle together with the right angle comprise two angles of the triangle. When two corresponding angles and a corresponding side (the side opposite the right angle) are congruent, the right triangles are congruent by the AAS theorem. (This can be referred to as the HA theorem.)

__

2. CM = DM; MA = MB; ∠A = ∠C = 90°, so all of the requirements for the HL theorem are met. ΔCMA ≅ ΔDMB, so AC ≅ BD by CPCTC.

__

3. TS = TV, TR = TR, ∠S = ∠V = 90°, so all requirements for the HL theorem are met. ΔTSR ≅ ΔTVR, so RS ≅ RV by CPCTC.

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2 years ago

Order the following numbers from least to greatest...

poizon [28]

Answer:

-25/3, $\sqrt{x} 15$ ,-pi/2,3pi

Step-by-step explanation:

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2 years ago

The volume of a cube is 343 cubic yards what is the length of the cube

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2 years ago

Car = V-8 sedan Years driven = first through third Miles driven = 14,000 miles each year In dollars and cents, the total project

saveliy_v [14]

Answer:

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Step-by-step explanation:

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2 years ago

Element X is a radioactive isotope such that its mass decreases by 26% every day. If an experiment starts out with 810 grams of

ioda

Answer:

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the amount of a substance is given by:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Hourly rate of change:

Decreases 26% by day. A day has 24 hours. This means that $A(24) = (1-0.26)A(0) = 0.74A(0)$ ; We use this to find r.

$A(t) = A(0)(1-r)^t$

$0.74A(0) = A(0)(1-r)^{24}$

$(1-r)^{24} = 0.74$

$\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}$

$1 - r = (0.74)^{\frac{1}{24}}$

$1 - r = 0.9875$

$r = 1 - 0.9875 = 0.0125$

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

Starts out with 810 grams of Element X

This means that $A(0) = 810$

Element X is a radioactive isotope such that its mass decreases by 26% every day.

This means that we use, for this equation, r = 0.26.

The equation is:

$A(t) = A(0)(1-r)^t$

$A(t) = 810(1 - 0.26)^t$

$A(t) = 810(0.74)^t$

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

5 0

2 years ago