Answer:
1) ![a^2](https://tex.z-dn.net/?f=a%5E2)
2) ![a^3](https://tex.z-dn.net/?f=a%5E3)
3) ![b^4](https://tex.z-dn.net/?f=b%5E4)
4) ![a^2b^2](https://tex.z-dn.net/?f=a%5E2b%5E2)
5) ![a^3b^2](https://tex.z-dn.net/?f=a%5E3b%5E2)
6) ![a^3b](https://tex.z-dn.net/?f=a%5E3b)
7) ![a^3b^2](https://tex.z-dn.net/?f=a%5E3b%5E2)
8) ![a^3b^2](https://tex.z-dn.net/?f=a%5E3b%5E2)
Step-by-step explanation:
1) a × a = ![a^2](https://tex.z-dn.net/?f=a%5E2)
2) a × a × a = ![a^3](https://tex.z-dn.net/?f=a%5E3)
3) b × b × b × b = ![b^4](https://tex.z-dn.net/?f=b%5E4)
4) a × a × b × b = ![a^2b^2](https://tex.z-dn.net/?f=a%5E2b%5E2)
5) a × a × a × b × b = ![a^3b^2](https://tex.z-dn.net/?f=a%5E3b%5E2)
6) a × a × b × a = ![a^3b](https://tex.z-dn.net/?f=a%5E3b)
7) a × b × a × a × b = ![a^3b^2](https://tex.z-dn.net/?f=a%5E3b%5E2)
8) b × a × a × a × b = ![a^3b^2](https://tex.z-dn.net/?f=a%5E3b%5E2)
Answer:
Lines are considered parallel if their slopes are the same. In Line 1, the slope is 5 and in Line 2, when we solve for 'y', we also get a slope of 5, which means the two lines are parallel.
Step-by-step explanation:
In order to find slope, it is easiest to put the equation in slope-intercept form, or y=mx + b, where m = slope and b=y-intercept. In L1, y=5x +1 indicates a slope of 5. In L2, the equation is not in slope-intercept form, so we must solve for 'y' using inverse operations: 2y - 10x +3 = 0, start by subtracting 3 from both sides of the equal sign: 2y - 10x +3 -3 = 0 - 3 gives us 2y - 10x = -3. Then add '10x' to both sides: 2y - 10x + 10x = -3 + 10x gives us 2y = 10x - 3. Lastly, divide all terms by 2: 2y/2 = (10/2)x - 3/2 or y = 5x - 1.5. Now that L2 is in slope-intercept form, we can see that m=5 as in L1, so since they have the same slope, they are parallel lines.
If the ratio is 4:3:2 each part of that ratio has a value of:
216/(4+3+2)
216/9=24
Since A pays four parts,
A pays 4*24=£96
<h3>Answer:</h3>
63 liters
<h3>Explanation:</h3>
The amount of fuel used per day is ...
... (1 tank - 2/3 tank)/(6 days) = (1/3 tank)/(6 days) = (1/18) tank/day
Then the amount of fuel used after 6+11 = 17 days is
... (17 days)×(1/18 tank/day) = 17/18 tank
and the amount remaining is ...
... (1 tank -17/18 tank) = 1/18 tank = 3 1/2 liters
To find the tank size, we can multiply this result by 18:
... 1 tank = 18×(3 1/2 liters) = 63 liters
Answer:
Chang ans Shaneka
Step-by-step explanation:
10:15 = 2:3
8:12 = 2:3