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Oksanka [162]
3 years ago
12

4.2 decreased by the quantity 12 plus a number

Mathematics
1 answer:
Illusion [34]3 years ago
5 0

Answer and Step-by-step explanation:

This is the same thing as:

<u>4.2 - (12 + x)</u>

The 4.2 is being subtracted by the value of 12 and a number, denoted as x.

<u><em>#teamtrees #PAW (Plant And Water)</em></u>

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Scott is on his school's academic team. On average, it takes Scott 4 minutes, with a standard deviation of 0.25 minutes, to solv
uysha [10]

Answer:

15.87% is the chance that Scott takes more than 4.25 minutes to solve a problem at an academic bowl.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4 minutes

Standard Deviation, σ = 0.25 minutes

We standardize the given data.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(more than 4.25 minutes to solve a problem)

P( x > 4.25) = P( z > \displaystyle\frac{4.25 - 4}{0.25}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 4.25) = 1 - 0.8413 = 0.1587 = 15.87\%

Thus,15.87% is the chance that Scott takes more than 4.25 minutes to solve a problem at an academic bowl.

8 0
2 years ago
Whoever checks my work and tell what I did wrong and the right answer will
gulaghasi [49]

Answer:

See below

Step-by-step explanation:

I believe that you only had to do letters F, H, and J. In that case, let's go over each one!

F: For isolatingd_{1}, we need to get rid of the 1/2 first. Let's multiply each side by 2:

2*m = 2*\frac{1}{2}(d_{1}+  d_{2}) \\2m = d_{1}+  d_{2}

After this, we just subtract d_{2} from each side to get d_{1}=2m- d_{2}. Dark Blue is correct! Let's now plug in those numbers below:

d_{1}=2(10)- 13 = 20-13=7

G: Let's isolate the vw^2 on one side by subtracting y from each side:

vw^{2} +y-y=x-y\\vw^{2}=x-y

Let's now divide each side by v, then put each side under a square root to get our final answer:

\frac{vw^2}{v} = \frac{x-y}{v}\\  w^2 =  \frac{x-y}{v}\\\sqrt{w^2} = \sqrt{\frac{x-y}{v}} \\w=\sqrt{\frac{x-y}{v}}

Orange is correct! Again, let's solve the problem underneath:

w=w=\sqrt{\frac{38-(-7)}{5}} = \sqrt{\frac{38+7}{5}} = \sqrt{\frac{45}{5}}=\sqrt{9}=3

H: This one has some stuff that we haven't worked with quite yet (like terms), but our approach is the same: isolate c on one side of the equation.

2a-2a+3c=17a-2a+21\\3c = 15a+21\\\frac{3c}{3} = \frac{15a+21}{3}\\c = \frac{15a}{3}+ \frac{21}{3} \\c = 5a+7

Purple is correct! Let's solve the problem:

c = 5(\frac{16}{5})+7 = 16+7 = 23

7 0
2 years ago
Twice the difference of a number and 1 is 4 more than that number. find a number using polyas 4 steps
professor190 [17]

Answer:

x=3

Step-by-step explanation:

2(x-1)=4

2x-2=4

2x=4+2

2x=6

x=6/2=3

8 0
3 years ago
Please Help!!<br><br>Use Euler’s formula to write in exponential form.
LekaFEV [45]

Answer:

C, 4e^{i(7\pi/4)}

Step-by-step explanation:

To remind you, Euler's formula gives a link between trigonometric and exponential functions in a very profound way:

e^{ix}=\cos{x}+i\sin{x}

Given the complex number 2\sqrt{2}-2i\sqrt{2}, we want to try to get it in the same form as the right side of Euler's formula. As things are, though, we're unable to, and the reason for that has to do with the fact that both the sine and cosine functions are bound between the values 1 and -1, and 2√2 and -2√2 both lie outside that range.

One thing we could try would be to factor out a 2 to reduce both of those terms, giving us the expression 2(\sqrt{2}-i\sqrt{2})

Still no good. √2 and -√2 are still greater than 1 and less than -1 respectively, so we'll have to reduce them a little more. With some clever thinking, you could factor out another 2, giving us the expression 4\left(\frac{\sqrt{2}}{2} -i\frac{\sqrt{2}}{2}\right) , and <em>now </em>we have something to work with.

Looking back at Euler's formula e^{ix}=\cos{x}+i\sin{x}, we can map our expression inside the parentheses to the one on the right side of the formula, giving us \cos{x}=\frac{\sqrt2}{2} and \sin{x}=-\frac{\sqrt2}{2}, or equivalently:

\cos^{-1}{\frac{\sqrt2}{2} }=\sin^{-1}-\frac{\sqrt2}{2} =x

At this point, we can look at the unit circle (attached) to see the angle satisfying these two values for sine and cosine is 7π/4, so x=\frac{7\pi}{4}, and we can finally replace our expression in parentheses with its exponential equivalent:

4\left(\frac{\sqrt2}{2}-i\frac{\sqrt2}{2}\right)=4e^{i(7\pi/4)}

Which is c on the multiple choice section.

4 0
3 years ago
Jim provides photos for two online sites: site A and site B. Site A pays $0.85 for every photo Jim provides. The amount in dolla
yarga [219]
We can use the same equation to figure out with only substituting the amount he was paid per photo.

Site A    y = $0.85x      =  $0.85(5)  =  $4.25
Site B    y = $0.40x      =  $0.40(5)  =  $2.00

We can see that Jim was paid $2.25 more at site A than Site B.
6 0
3 years ago
Read 2 more answers
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