A(-4,5)
B(-2,8)
C(1,2)
up= addition to y
down= subtraction to y
right= addition to x
left= substraction to x
Area of the rectangular mat = 12 x 4 = 48 in²
Area of the 3 circles = 3( πr²) = 3(3.14 x 2²) = 37.68 in²
P(landing in a circle) = 37.68/48 = 157/200 = 0.79 (nearest hundredth)
Answer: The probability of landing in one of the circles is 0.79.
Answer:
k=3 z=-6
Step-by-step explanation:
12k=36
k=36/12
k=3
-6z=36
z=36/-6
z=-6
12(3)-6(-6)=36
8/12 and 2/3
7/10 and 21/30
These are the ones that are equivalent. The others are not.
Answer:
I actually needed help with the answer but now I think about it the answer is answer C. $50
Step-by-step explanation: