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Answer:
Step-by-step explanation:
Given that special deck of cards has 20 cards. Nine are green, seven are blue, and four are red. When a card is picked, the color of it is recorded. An experiment consists of first picking a card and then tossing a coin
A) Sample space will have Green, Head, or Green, Tail .... Red, head, red, tail
No of elements in sample space = no of colours x no of outcomes in coin toss
= 4x2 = 8
B) A= getting (RT)
P(A) = Prob of getting red card and tail on coin
= P (R) *P(T)
=
C) B be the event that a green or blue is picked, followed by landing a tail on the coin toss
B = getting green card and tail
Getting green card tail is mutally exclusive with red card and tail as there is no common element between green and blue.
D) C= red or green card is picked followed by tail.
Here A and C have a common element as getting red and tail. So not mutually exclusive
You then would eliminate 6, by adding 6 to both sides
Then you want all of the X's on the same side, so you subtract 2x from both sides.
Then to isolate the X, you divide by 2
The answer is x=2