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igomit [66]
3 years ago
7

I need help!!

Mathematics
1 answer:
Natasha2012 [34]3 years ago
7 0

Answer:

The exact solution is

x = \frac{Ln(60)}{7*Ln(5)}

And the approximation to three decimal places is:

x = 0.363

Step-by-step explanation:

Here we have the equation:

5^{7*x} = 60\\

Now we can remember a property of the natural logarithm function:

Ln(a^n) = n*Ln(a)

Now we can apply the Ln( ) function to both sides of that equation to get:

Ln(5^{7*x}) = Ln(60)

Then we get:

7*x*Ln(5) = Ln(60)

Solving that for x we get:

x = \frac{Ln(60)}{7*Ln(5)}  = 0.363

So the exact solution is:

x = \frac{Ln(60)}{7*Ln(5)}

And the approximation to three decimal places is:

x = 0.363

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3 years ago
Please i need an answer urgently. Sum of 3 terms are 252, first term is 192. Find common ratio
Viefleur [7K]

Answer:

r=\frac{1}{4}\\\\r=-\frac{5}{4}

Step-by-step explanation:

<u>Geometric Sequences</u>

The geometric sequence is given as:

a_1, a_1r, a_1r^2, a_1r^3,..., a_1r^{n-1}

Where n is the number of the term, n≥1, and r is the common ratio.

The sum of n terms of the geometric sequence is given by:

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We are given: S3=252, a1=192, thus substuting:

\displaystyle 252=192\frac{r^3-1}{r-1}

Dividing by 12:

\displaystyle 21=16\frac{r^3-1}{r-1}

Recall that:

r^3-1=(r-1)(r^2+r+1)

Substituting:

\displaystyle 21=16\frac{(r-1)(r^2+r+1)}{r-1}

Simplifying:

21=16(r^2+r+1)=16r^2+16r+16

Rearranging:

16r^2+16r+16-21=0

16r^2+16r-5=0

Rewriting:

16r^2-4r+20r-5=0

Factoring:

4r(4r-1)+5(4r-1)=0

(4r-1)(4r+5)=0

Solving:

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Both solutions are valid

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