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Rudik [331]
3 years ago
7

5 for every $2.50 10 for every ?​

Mathematics
1 answer:
Anit [1.1K]3 years ago
8 0

Answer:

5 dollars

you do 2.50 x 2 because 5 x 2 makes 10, and you have to do what you do to one side, to the other.

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If the point (2,5) is on the graph of an equation, which statement must be
Hunter-Best [27]

Answer: D

Step-by-step explanation:

The values x = 2 and y = 5 make the equation true.

4 0
3 years ago
Can anyone help me I am stuck on this question! and tysm for the people who helped me! <3 Have a nice day!
Rainbow [258]

Answer:

115.24

Step-by-step explanation:

15.35*4.25=65.2375

65.2375+50=115.2375

115.2375 ≈ 115.24

8 0
2 years ago
A foreign student club lists as its members 2 Canadians, 3 Japanese, 5 Italians, and 2 Germans. If a committee of 4 is selected
Fittoniya [83]

Answer:

(a) The probability that the members of the committee are chosen from all nationalities =\frac{4}{33}  =0.1212.

(b)The probability that all nationalities except Italian are represent is 0.04848.

Step-by-step explanation:

Hypergeometric Distribution:

Let x_1, x_2, x_3 and x_4 be four given positive integers and let x_1+x_2+x_3+x_4= N.

A random variable X is said to have hypergeometric distribution with parameter x_1, x_2, x_3 , x_4  and n.

The probability mass function

f(x_1,x_2.x_3,x_4;a_1,a_2,a_3,a_4;N,n)=\frac{\left(\begin{array}{c}x_1\\a_1\end{array}\right)\left(\begin{array}{c}x_2\\a_2\end{array}\right) \left(\begin{array}{c}x_3\\a_3\end{array}\right) \left(\begin{array}{c}x_4\\a_4\end{array}\right)  }{\left(\begin{array}{c}N\\n\end{array}\right) }

Here a_1+a_2+a_3+a_4=n

{\left(\begin{array}{c}x_1\\a_1\end{array}\right)=^{x_1}C_{a_1}= \frac{x_1!}{a_1!(x_1-a_1)!}

Given that, a foreign club is made of  2 Canadian  members, 3 Japanese  members, 5 Italian  members and 2 Germans  members.

x_1=2, x_2=3, x_3 =5 and x_4=2.

A committee is made of 4 member.

N=4

(a)

We need to find out the probability that the members of the committee are chosen from all nationalities.

a_1=1, a_2=1,a_3=1 , a_4=1, n=4

The required probability is

=\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\1\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right)  }{\left(\begin{array}{c}12\\4\end{array}\right) }

=\frac{2\times 3\times 5\times 2}{495}

=\frac{4}{33}

=0.1212

(b)

Now we find out the probability that all nationalities except Italian.

So, we need to find out,

P(a_1=2,a_2=1,a_3=0,a_4=1)+P(a_1=1,a_2=2,a_3=0,a_4=1)+P(a_1=1,a_2=1,a_3=0,a_4=2)

=\frac{\left(\begin{array}{c}2\\2\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right)  }{\left(\begin{array}{c}12\\4\end{array}\right) }+\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\2\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right)  }{\left(\begin{array}{c}12\\4\end{array}\right) }+\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\2\end{array}\right)  }{\left(\begin{array}{c}12\\4\end{array}\right) }

=\frac{1\times 3\times 1\times 2}{495}+\frac{2\times 3\times 1\times 2}{495}+\frac{2\times 3\times 1\times 1}{495}

=\frac{6+12+6}{495}

=\frac{8}{165}

=0.04848

The probability that all nationalities except Italian are represent is 0.04848.

6 0
3 years ago
Can anyone help me with this please?
anastassius [24]
You are taking off 8 each 2 at x, so it would be four for each 1 at x. therefore 2 is 9, 1 is 13 and...

the value of y is 17 when x = 0

sorry if i explained that bad
8 0
3 years ago
Plz I need help with geometry homework FIND THE ANGLES
Talja [164]

Answer:

  1. a = 36°
  2. b = 36°
  3. c = 72°
  4. d = 72°
  5. e = 108°
  6. f = 16°
  7. g = 74°
  8. h = 70°

Step-by-step explanation:

You are expected to know and make use of the following relations:

  • vertical angles are congruent
  • angles of a linear pair are supplementary
  • angles of a triangle sum to 180°
  • alternate interior angles are congruent (at parallel lines)
  • corresponding angles are congruent (at parallel lines)
  • acute angles of a right triangle are complementary
  • base angles of an isosceles triangle are congruent

__

For this problem, it isn't always easiest to work the questions in order. It is best to start with the angles easiest to find from those given.

  b and 144° are a linear pair, so b = 180° -144° = 36°

  a and b are alternate interior angles, so a = b = 36°

  2d and 144° are corresponding angles, so d = 144°/2 = 72°

  e is the apex angle of an isosceles triangle with base angles 36°, so is 180° -2(36°) = 108° = e

  f and 164° are a linear pair, so f = 180° -164° = 16°

  g and f are complementary, so g = 90° -16° = 74°

  g+h is a vertical angle with 144°, so is congruent to that. h = 144° -74° = 70°

  c is the base angle of an isosceles triangle with b as the vertex angle. That means c = (180° -36°)/2 = 72°

3 0
3 years ago
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