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3 years ago

5 for every $2.50 10 for every ?

Mathematics

1 answer:

Anit [1.1K]3 years ago

8 0

Answer:

5 dollars

you do 2.50 x 2 because 5 x 2 makes 10, and you have to do what you do to one side, to the other.

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If the point (2,5) is on the graph of an equation, which statement must be

Hunter-Best [27]

Answer: D

Step-by-step explanation:

The values x = 2 and y = 5 make the equation true.

4 0

3 years ago

Can anyone help me I am stuck on this question! and tysm for the people who helped me! <3 Have a nice day!

Rainbow [258]

Answer:

115.24

Step-by-step explanation:

15.35*4.25=65.2375

65.2375+50=115.2375

115.2375 ≈ 115.24

8 0

2 years ago

A foreign student club lists as its members 2 Canadians, 3 Japanese, 5 Italians, and 2 Germans. If a committee of 4 is selected

Fittoniya [83]

Answer:

(a) The probability that the members of the committee are chosen from all nationalities $=\frac{4}{33}$ =0.1212.

(b)The probability that all nationalities except Italian are represent is 0.04848.

Step-by-step explanation:

Hypergeometric Distribution:

Let $x_1$ , $x_2$ , $x_3$ and $x_4$ be four given positive integers and let $x_1+x_2+x_3+x_4= N$ .

A random variable X is said to have hypergeometric distribution with parameter $x_1$ , $x_2$ , $x_3$ , $x_4$ and n.

The probability mass function

$f(x_1,x_2.x_3,x_4;a_1,a_2,a_3,a_4;N,n)=\frac{\left(\begin{array}{c}x_1\\a_1\end{array}\right)\left(\begin{array}{c}x_2\\a_2\end{array}\right) \left(\begin{array}{c}x_3\\a_3\end{array}\right) \left(\begin{array}{c}x_4\\a_4\end{array}\right) }{\left(\begin{array}{c}N\\n\end{array}\right) }$

Here $a_1+a_2+a_3+a_4=n$

${\left(\begin{array}{c}x_1\\a_1\end{array}\right)=^{x_1}C_{a_1}= \frac{x_1!}{a_1!(x_1-a_1)!}$

Given that, a foreign club is made of 2 Canadian members, 3 Japanese members, 5 Italian members and 2 Germans members.

$x_1$ =2, $x_2$ =3, $x_3$ =5 and $x_4$ =2.

A committee is made of 4 member.

N=4

(a)

We need to find out the probability that the members of the committee are chosen from all nationalities.

$a_1$ =1, $a_2$ =1, $a_3$ =1 , $a_4$ =1, n=4

The required probability is

$=\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\1\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right) }{\left(\begin{array}{c}12\\4\end{array}\right) }$

$=\frac{2\times 3\times 5\times 2}{495}$

$=\frac{4}{33}$

=0.1212

(b)

Now we find out the probability that all nationalities except Italian.

So, we need to find out,

$P(a_1=2,a_2=1,a_3=0,a_4=1)+P(a_1=1,a_2=2,a_3=0,a_4=1)+P(a_1=1,a_2=1,a_3=0,a_4=2)$

$=\frac{\left(\begin{array}{c}2\\2\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right) }{\left(\begin{array}{c}12\\4\end{array}\right) }+\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\2\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right) }{\left(\begin{array}{c}12\\4\end{array}\right) }$ $+\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\2\end{array}\right) }{\left(\begin{array}{c}12\\4\end{array}\right) }$

$=\frac{1\times 3\times 1\times 2}{495}+\frac{2\times 3\times 1\times 2}{495}+\frac{2\times 3\times 1\times 1}{495}$

$=\frac{6+12+6}{495}$

$=\frac{8}{165}$

=0.04848

The probability that all nationalities except Italian are represent is 0.04848.

6 0

3 years ago

Can anyone help me with this please?

anastassius [24]

You are taking off 8 each 2 at x, so it would be four for each 1 at x. therefore 2 is 9, 1 is 13 and...

the value of y is 17 when x = 0

sorry if i explained that bad

8 0

3 years ago

Plz I need help with geometry homework FIND THE ANGLES

Talja [164]

Answer:

a = 36°
b = 36°
c = 72°
d = 72°
e = 108°
f = 16°
g = 74°
h = 70°

Step-by-step explanation:

You are expected to know and make use of the following relations:

vertical angles are congruent
angles of a linear pair are supplementary
angles of a triangle sum to 180°
alternate interior angles are congruent (at parallel lines)
corresponding angles are congruent (at parallel lines)
acute angles of a right triangle are complementary
base angles of an isosceles triangle are congruent

For this problem, it isn't always easiest to work the questions in order. It is best to start with the angles easiest to find from those given.

b and 144° are a linear pair, so b = 180° -144° = 36°

a and b are alternate interior angles, so a = b = 36°

2d and 144° are corresponding angles, so d = 144°/2 = 72°

e is the apex angle of an isosceles triangle with base angles 36°, so is 180° -2(36°) = 108° = e

f and 164° are a linear pair, so f = 180° -164° = 16°

g and f are complementary, so g = 90° -16° = 74°

g+h is a vertical angle with 144°, so is congruent to that. h = 144° -74° = 70°

c is the base angle of an isosceles triangle with b as the vertex angle. That means c = (180° -36°)/2 = 72°

3 0

3 years ago

5 for every $2.50 10 for every ?​

5 for every $2.50 10 for every ?