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vovikov84 [41]
3 years ago
11

Number 1 and 2 to lease help

Mathematics
1 answer:
Leno4ka [110]3 years ago
4 0

Answer:

1.y=0.5x

2.y=2x+1

Step-by-step explanation:

slope = y2-y1/x2-x1

y-y1=slope(x-x1)

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HELP HELP WITH MATH PLEASE
Karolina [17]
Should be 2/3 i think?
4 0
3 years ago
A rectangle is 6 feet long and 4 feet wide. If each dimension is increased by the same number of feet, a new rectangle is formed
Fofino [41]

Answer:

Each dimension increased by 3 ft.

Step-by-step explanation:

Area of the original rectangle = 4 * 6 = 24 square feet

Increased dimension = x ft

New length = 6 + x

New width = 4 +x

New area = (6 + x)(4 +x)    {Use FOIL method}

                = 6*4 + 6*x + x*4 + x*x

                = 24 + 6x + 4x + x²

                = x² + 10x + 24

New area = 24 + 39

x² + 10x + 24 = 63

x² +10x + 24 - 63 = 0

x² + 10x  - 39 = 0

x² + 13x - 3x  - 3*13 = 0

x (x + 13) - 3(x + 13) = 0

(x + 13)(x -3) = 0   {Ignore x + 13, as it gives negative value}

x - 3 = 0

x = 3

5 0
3 years ago
Solve for x:<br> |3x-1|=4
Rashid [163]

Answer:

x = 5/3  x= -1

Step-by-step explanation:

|3x-1|=4

There are two solutions to the absolute value equation, one positive and one negative

3x-1 =4  and 3x-1=-4

Add 1 to each side

3x-1+1 = 4+1   3x-1+1 = -4+1

3x=5             3x = -3

Divide by 3

3x/3 = 5/3     3x/3 = -3/3

x = 5/3  x= -1

5 0
3 years ago
Can someone help me please only do it if you know geometry
Sloan [31]

Answer: i am not sure with the answer but need point pls help

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Question is from definite integral.
Karolina [17]

Answer:

The value of the sum is: $ \frac{\pi}{4} $.

Step-by-step explanation:

Given: $ \lim_{n \to \infty} \displaystyle \sum_{k = 1}^ {n} \bigg ( \frac{n}{n^2 + k^2} \bigg ).

Taking $ n^2 $ common outside from the denominator, we have:

$ \bigg ( \frac{n}{(n^2)(1 + (\frac{k^2}{n^2})} \bigg )

\implies\frac{1}{n} .\frac{1}{1 +\big (  \frac  {k^2}{n^2}\big )}

We have the following theorem.

If $f $ is integrable on [0, 1] then $ \int _{0}^{1} f(x) dx = \lim_{n \to \infty} \frac{1}{n} \displaystyle \sum_{r = 1}^{n} f( \frac{x}{n})    $.

Now, let $ \frac{k}{n} = x $

$ \implies dx = \frac{1}{n} $.

Therefore the summation becomes

$ = \int_{0}^{1} \bigg ( \frac{1}{1 + x^2} \bigg )

$ \implies \tan^{-1}(x)|_{0}^{1} $

$ \implies tan^{-1}(1) - tan^{-1}(0) $

$ = \frac{\pi}{4}  - 0 $

$ = \frac{\pi}{4} $

Hence, the sum is $ \pi $/4.

4 0
4 years ago
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