Answer:
43.35 years
why?
From the above question, we are to find Time t for compound interest
The formula is given as :
t = ln(A/P) / n[ln(1 + r/n)]
A = $2500
P = Principal = $200
R = 6%
n = Compounding frequency = 1
First, convert R as a percent to r as a decimal
r = R/100
r = 6/100
r = 0.06 per year,
Then, solve the equation for t
t = ln(A/P) / n[ln(1 + r/n)]
t = ln(2,500.00/200.00) / ( 1 × [ln(1 + 0.06/1)] )
t = ln(2,500.00/200.00) / ( 1 × [ln(1 + 0.06)] )
t = 43.346 years
(credit to VmariaS)
Answer:
y=5/4x+7
Step-by-step explanation:
Honestly, I just guessed and checked, but here is a picture of evidence.
Answer:
Step-by-step explanation:
Hello!
You need to construct a 95% CI for the population mean of the length of engineering conferences.
The variable has a normal distribution.
The information given is:
n= 84
x[bar]= 3.94
δ= 1.28
The formula for the Confidence interval is:
x[bar]±
*(δ/n)
Lower bound(Lb): 3.698
Upper bound(Ub): 4.182
Error bound: (Ub - Lb)/2 = (4.182-3.698)/2 = 0.242
I hope it helps!
the error is that they didnt add the exponets
It’s really hard to see the picture