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2 years ago

10

Help! This is prob an easy question since it’s for Hunter prep, but I have no idea how to do it. If you could answer, that would

be nice. Thanks! :)

1 answer:

olga_2 [115]2 years ago

3 0

Answer: I think it would be option E

Step-by-step explanation:

If my answer helps u plz add me as brainliest.

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Drag the tiles to the correct boxes to complete the pairs. Find the distance between each pair of points. 5 units 4 units 2 unit

Olin [163]

Answer:

a) Distance between points A (5, 4) and B( 5, -2) is 6 units

b) Distance between points E (-2, -1) and F( -2, -5) is 4 units

c) Distance between points C (-4, 1) and D( 1, 1) is 5 units

d) Distance between points G(3, -5) and H(6, -5) is 3 units

Step-by-step explanation:

We need to find the distance between each pair

a) A (5, 4) and B( 5, -2)

the distance formula is:

$d(A,B) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = 5, x₂=5 and y₁= 4 and y₂= -2

$d(A,B) = \sqrt{(5-5)^2+(-2-4)^2}$

$d(A,B) = \sqrt{(0)^2+(-6)^2}$

$d(A,B) = \sqrt{36}$

$d(A,B) = 6$

Distance between points A (5, 4) and B( 5, -2) is 6 units

b) E (-2, -1) and F( -2, -5)

the distance formula is:

$d(E,F) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = -2, x₂=-2 and y₁= -1 and y₂= -5

$d(E,F) = \sqrt{(-2-(-2))^2+(-5-(-1))^2}$

$d(E,F) = \sqrt{(0)^2+(-4)^2}$

$d(E,F) = \sqrt{16}$

$d(E,F) = 4$

Distance between points E (-2, -1) and F( -2, -5) is 4 units

c) C (-4, 1) and D( 1, 1)

the distance formula is:

$d(C,D) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = -4, x₂=1 and y₁= 1 and y₂= 1

$d(C,D)= \sqrt{(1-(-4))^2+(1-(1))^2}$

$d(C,D) = \sqrt{(5)^2+(0)^2}$

$d(C,D) = \sqrt{25}$

$d(C,D) = 5$

Distance between points C (-4, 1) and D( 1, 1) is 5 units

d) G(3, -5) and H(6, -5)

the distance formula is:

$d(G,H) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = 3, x₂=6 and y₁= -5 and y₂= -5

$d(G,H)= \sqrt{(6-(3))^2+(-5-(-5))^2}$

$d(G,H) = \sqrt{(3)^2+(0)^2}$

$d(G,H) = \sqrt{9}$

$d(G,H) = 3$

Distance between points G(3, -5) and H(6, -5) is 3 units

8 0

3 years ago

Jayden works for Float like a butterfly sting like a bee boxing club and received 660 on his last paycheck. If he gets paid time

alexandr402 [8]

Answer:

He make an hour if he worked 50 hours= 275

Step-by-step explanation:

Jayden worked for Float like a butterfly sting like a bee boxing club and received 660 on his last paycheck. Suppose he gets paid time and a half for overtime. How much does he make an hour if he worked 50 hours?

Sol: Jayden received on his last paycheck = 660

Half for over time = 660/2 = 330

Paid time = 660 - 330 = 330

In 50 hours he makes = 330 x 50 = 16500

In one hour he makes = 16500/60 ( 1 hour = 60 min)

= 275

4 0

3 years ago

Kieran subscribes to a text messaging service on his cell phone. His monthly bill for the service is given by the equation b = 0

Lemur [1.5K]

B=1.25 so i think im not so good with this but i try if its wrong nvr listen to me

3 0

3 years ago

Read 2 more answers

Rewrite each expression without using absolute value notation |7m-56| if m<8

dusya [7]

Considering the definition of the absolute value function, the expression is written as -7m + 56.

<h3>What is the definition of the absolute value function?</h3>

The absolute value function is defined as follows:

$|x| = x, x \geq 0$ .

$|x| = -x, x < 0$

That is, where the expression is negative, it is multiplied by -1, while where it is not negative the expression is kept.

In this problem, the expression is:

|7m - 56|

For m < 8, we have that one example is m = 0:

7(0) - 56 = -56.

The expression is negative, hence the signal is changed, that is:

|7m - 56| = -(7m - 56) = -7m + 56.

More can be learned about the absolute value function at brainly.com/question/24734454

#SPJ1

7 0

1 year ago

1- El area de un cuadrado es igual a 8 veces la medida de su lado ¿ Cuánto mide por lado el cuadrado?

Papessa [141]

El área de un cuadrado es igual a 8 veces la medida de su lado. ¿Cuánto mide por lado el cuadrado ?

El Area de un Cuadrado es : A = L²

L² = 8 x L -------------> L² / L = 8 ----------> L = 8

Cada lado mide 8 unidades.

2) El triple del área de un cuadrado menos seis veces la medida de su lado es igual a cero ¿Cuánto mide por lado el cuadrado?

El Area de un Cuadrado es : A = L²

(3 x L²) - 6 L = 0

Factorizando : 3L ( L - 2 ) = 0 --------> L = 0 ; L = 2

Cada lado mide 2 unidades.

3 0

2 years ago